I've been stuck on this for hours and I still haven't found the right order for this number square. | Mathematics | Page 1

boreal ridge Jan 12, 2025, 1:28 PM

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golden rampartBOT Jan 12, 2025, 1:29 PM

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boreal ridge

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boreal ridge Jan 12, 2025, 1:36 PM

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I know the 8 goes there since it's the only number that's fits the symbol but everything else is a lost cause for me

misty spade Jan 12, 2025, 1:42 PM

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I found the solution

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do you want it, or just a hint?

boreal ridge Jan 12, 2025, 1:43 PM

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I want to know the right thinking process to solve this so yeah a hint, I know that the symbols like square root narrow down the numbers but theres still too many combinations

misty spade Jan 12, 2025, 1:43 PM

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Okay, I will explain how i found it

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the 8 was a good starting point

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the square below could only be 1 or 2, because otherwise we wouldnt have round numbers

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then the one below that can only be 4 or3

boreal ridge Jan 12, 2025, 1:46 PM

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alright I'll keep that in mind

misty spade Jan 12, 2025, 1:46 PM

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then the middle one on the bottom can only be 9 or 4

misty spade Jan 12, 2025, 1:47 PM

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boreal ridge alright I'll keep that in mind

You understand why what i say is true?

boreal ridge Jan 12, 2025, 1:48 PM

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right, because if you're dividing the 8 by a number it has to be something that can later be subracted to equal the whole negative number

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(-2)

misty spade Jan 12, 2025, 1:48 PM

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exactly

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should i go on, or do you want some time to find it yourself first?

boreal ridge Jan 12, 2025, 1:49 PM

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I'll give it a shot and tell you how I go

misty spade Jan 12, 2025, 1:52 PM

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boreal ridge right, because if you're dividing the 8 by a number it has to be something that ...

btw, its not the 8 that you divide, but the cube root of 8: 2 that you can only divide by 1 or 2

boreal ridge Jan 12, 2025, 1:52 PM

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alr

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mb on the oversight

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also for the right side middle, since the number's 111 and the only two options to put there are 1 and 2, if you put 2 there'd be a decimal involved so that's out of the question, the middle right box has to be 1

misty spade Jan 12, 2025, 2:04 PM

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how do you mean?

boreal ridge Jan 12, 2025, 2:06 PM

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misty spade btw, its not the 8 that you divide, but the cube root of 8: 2 that you can only ...

okay so it says that a number to the power of three, minus a number, times an number would = 111. We've established from this message that the middle right box has two options, 1 and 2. Let's say you put two in that box, you divide 111 by 2 and that'd be a decimal. There are only whole numbers as options.

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meaning that a number to the power of 3 minus a number should equal 111, then you'd times it by 1 in the end

misty spade Jan 12, 2025, 2:08 PM

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no, you have to pay attention to the order of operations

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you have to do the multiplication first, en after that the subtraction

boreal ridge Jan 12, 2025, 2:09 PM

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boreal ridge meaning that a number to the power of 3 minus a number should equal 111, then yo...

alright so screw this part then, but is my thought in general right?

misty spade Jan 12, 2025, 2:10 PM

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it has to be a two

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not a one

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ill explain

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so i ended at the middle one at the bottom, the next one is the bottom right one, any ideas?

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you know that the middle bottom one can only be 9 or 4 because of the root, so the result will be 2 or 3

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then you have to divide it, by 3 or 4(which we discussed earlier)

boreal ridge Jan 12, 2025, 2:12 PM

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yeah Im following

misty spade Jan 12, 2025, 2:13 PM

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so the only way to maintain whole numbers, is the 3 idvided by 3

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you see?

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en then the bottom left one is easy

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you following?

boreal ridge Jan 12, 2025, 2:13 PM

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mhm

misty spade Jan 12, 2025, 2:15 PM

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where did i lose you?

boreal ridge Jan 12, 2025, 2:15 PM

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we at this right?

misty spade Jan 12, 2025, 2:15 PM

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yes

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and then the middle right one, it was 1 or 2, so it should be:

boreal ridge Jan 12, 2025, 2:16 PM

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2

misty spade Jan 12, 2025, 2:16 PM

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indeed

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the last 4 are a bit more tricky

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ill explain what i did

boreal ridge Jan 12, 2025, 2:17 PM

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misty spade the last 4 are a bit more tricky

I feel like trial and error should be enough from here but sure, go on

misty spade Jan 12, 2025, 2:17 PM

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so i started with the left column

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(yes its a bit trial and error)

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so i wrote x^2 + y^3 =141

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so x = sqrt(141 - y^3)

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and then i started to put different numbers in y to see wher i got a whole number for x, that is still availeble

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so i started with 4

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then you get sqrt(77) or something

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so not right

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when you put in 5, you get sqrt(16)

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so 4

boreal ridge Jan 12, 2025, 2:20 PM

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quick question what's sqrt?

misty spade Jan 12, 2025, 2:20 PM

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square root

boreal ridge Jan 12, 2025, 2:20 PM

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ahh, got it

misty spade Jan 12, 2025, 2:21 PM

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and then the other two are fairly easy

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(assuming 4 and 5 is the only possible combination)

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you understand?

boreal ridge Jan 12, 2025, 2:21 PM

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yeah

misty spade Jan 12, 2025, 2:22 PM

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let me know when you found the final solution

boreal ridge Jan 12, 2025, 2:23 PM

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alright

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This should be it right? (Funny thing is Im sorta seeing alot of combinations I've already messed with before lol)

misty spade Jan 12, 2025, 2:26 PM

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Yes that looks perfect

boreal ridge Jan 12, 2025, 2:27 PM

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Thank you SOOOO much bro you don't know how much I appreciate your help 🙏

misty spade Jan 12, 2025, 2:27 PM

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No problem man, I am happy I could help you

boreal ridge Jan 12, 2025, 2:27 PM

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thanks again, have a good one 👋

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+close

#I've been stuck on this for hours and I still haven't found the right order for this number square.