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19 messages · Page 1 of 1 (latest)
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well, do just that.
flip the fraction z into 1/z, then multiply by the conjugate on the top and bottom
j, I take it, is the imaginary unit?
yes
show your work, plz
$$ \frac{a+ib}{c+id} = \frac{(a+ib)(c-id)}{(c+id)(c-id)} = \frac{(a+ib)(c-id)}{c^2+d^2} $$
aL
this is how it's usually done
@woven bolt
you didn't have to do that much work but...yeah its the right answer
haha thank you
I am shitting myself with uni work
Maths was never really my thing man
you could have just noted this
if $z=\frac{a}{b}$ then $\frac{1}{z}=\frac{b}{a}$
temu mod | promote to mod pls
Ill keep it in mind, thank you