#For school, can someone help me
57 messages · Page 1 of 1 (latest)
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No need to round your answers.
Also, b is wrong.
Only b or anything else?
Only b is wrong. The others are correct, but you shouldn't round the answers. And they could be solved in slightly better ways.
Idk, I solved it by some examples in the book, but my lecture book isn’t in English, so I don’t really know if you would understand the message of this book
Why would I not understand it?
Anyway.
For example, I'd solve (a) like this.
e^(-x) = 1/10
-x = ln(1/10) = -ln(10)
x = ln(10)
That’s the examples from the book
I tried to implement them in my calculation
Anyways, but why is b wrong?
Oh, you meant it is not in English.
Yes
Sry type error
But I understood my mistake now
Ah, alright, nice!
I have approximately 1,3863 for b now
Yes, x = 2ln(2) in (b).
Again, why round?
Idk because I’m lazy and don’t want to write the whole thing after the comma 😭
What?
I round always if I can actually , never had problems with that
That's not a correct way to solve a math problem.
In math if you don't have to round, you don't.
My teacher also says, if there are too many numbers, you can round that
Idk
What do you mean? It's an irrational number, it has infinitely many decimal points.
I meant that you should just leave it as x = 2ln(2).
Very strange approach...
You’re right
Idk I will show up to her
And ask her
But again, we round always, never had any problems
That's just not how you solve math problems.
You round in, say, physics or chemistry, and only at the end of your calculatuions.
You almost never round anything in math problems.
But with approximately-equal-sign you can round, can’t you?
But why, though?
Why not just leave it exact, as x = 2ln(2)?
It doesn’t feel right to me yk?
I want to see numbers
To understand what I actually wrote
What should I begin with x = 2ln(2)?
What do you mean? That's the answer for (b).
That's it.
I don't understand what you mean, sorry.
@honest shale
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