#graph

50 messages · Page 1 of 1 (latest)

pseudo pasture
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--

iron leafBOT
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stray ibexBOT
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pseudo pasture
primal scroll
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Same principle as before: find two integer grid points, use the equation.

pseudo pasture
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(1,-1)

primal scroll
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No, the line doesn't pass through (1, -1)...

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Wait.

pseudo pasture
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it doesn't ?

primal scroll
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Can you pinpoint on the graph where you think the point (1, -1) is?

pseudo pasture
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ya, brb

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down the corridors n up the stairs ?

primal scroll
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Oh! Wait, my bad.

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The picture didn't load in the greatest quality, so I though it passed through (1, 0), instead.

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(1, -1) is good.

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And another point?

pseudo pasture
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ayy

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brb

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(0,5)

primal scroll
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Yeah, that works.

pseudo pasture
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okok

pseudo pasture
primal scroll
pseudo pasture
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an example of the structure ? please

primal scroll
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Oh.
Well, suppose a line passes through points (3, 5) and (6, 11). Then its equation is:
(x - 3)/(6 - 3) = (y - 5)/(11 - 5)
(x - 3)/3 = (y - 5)/6
y - 5 = 2(x - 3)
y = 2x - 1

pseudo pasture
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ah what

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okok

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so

primal scroll
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You just apply the formula and simplify.

pseudo pasture
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am lost again

primal scroll
# pseudo pasture

That's not correct.
The equation is (x - x1)/(x2 - x1) = (y - y1)/(y2 - y1), so in our case that would be (x - 1)/(0 - 1) = (y + 1)/(5 + 1).
Also, why write fractions like that?

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You should write them vertically, as usual.

pseudo pasture
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like what ?

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oh

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it's easier cause I don't have a ruler atm

primal scroll
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Why do you need a ruler?

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We don't need to draw this line, we just need to write its equation.

pseudo pasture
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oh, I meant for the fraction--

primal scroll
pseudo pasture
primal scroll
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You're welcome!

obsidian nimbusBOT
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@pseudo pasture

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pseudo pasture
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oh mb

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+close

obsidian nimbusBOT
# pseudo pasture +close
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obsidian nimbusBOT
# obsidian nimbus

Thank you for your feedback! LordDarpinger #cyclopentadiene has been awarded 1 helper_points. They now have 24 helper_points. They have 2 helper_points daily left for today.