#simple linear eq. (please help I'm really stupid)

36 messages · Page 1 of 1 (latest)

vernal creek
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okay, I got redundant column. What is the result of this linear eq? [-1, 0, 0, -1, 1], # -x1 - x4 = 1 [0, 0, 0, 0, 0], # 0 = 0 (redundant) [0, 1, 0, 4, -3], # x2 + 4*x4 = -3 [0, 0, 1, 3, -4] # x3 + 3*x4 = -4

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i simply need the x1,x2,x3,x4

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lol

frigid jackal
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Have you tried even extracting the linear equations?

vernal creek
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−x1 −x4 = 1
x2 +4x4 = −3
2x1 +x3 +5x4 = −6```
frigid jackal
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Now use the t method

vernal creek
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i will try

vernal creek
frigid jackal
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Try representing it as $x_4$

little narwhalBOT
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TabMineCrafter

vernal creek
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ѕо confusing lol despair

frigid jackal
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try representing it as x4

vernal creek
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ok

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i will try to calculate that

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is there a solution then?

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I guess not right?

frigid jackal
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Un

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Um

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There are

frigid jackal
frigid jackal
vernal creek
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thx

frigid jackal
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They are the ones by the #

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# 0 = 0 (redundant)
# x2 + 4*x4 = -3
# x3 + 3*x4 = -4```
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These are

frigid jackal
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,ti @vernal creek

little narwhalBOT
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This user hasn't set their timezone! Ask them to set it using ,ti --set.

vernal creek
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[
\begin{aligned}
x_1 &= -t - 1, \
x_2 &= -4t - 3, \
x_3 &= -3t - 4, \
x_4 &= t,
\end{aligned}
]

little narwhalBOT
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MiniNGC

vernal creek
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that's my solution to that shit

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@frigid jackal thanks bro!

frigid jackal
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Right