#Find the area of the intersection of the two disks, in cm2
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storm grove
Let's look at a more general case: circles of radius r and R, whose centers are distance d < r + R from each other.
Then if we also draw a perpendicular line segment y, then we have:
x^2 + y^2 = r^2
(d - x)^2 + y^2 = R^2
So, now you can subtract these equations and solve for x. After that you can find all the relevant angles.
solar pulsar
x= r^2-R^2+d^2\2d , sorry but i don't understand how it should help me to find the relevant angels
storm grove
x= r^2-R^2+d^2\2d , sorry but i don't understand how it should help me to find t...
Well, now look at two right triangles. We have:
cos(α) = x/r = (d^2 + r^2 - R^2)/(2dr)
cos(β) = (d - x)/R = (d - (d^2 + r^2 - R^2)/(2d))/R = (d^2 - r^2 + R^2)/(2dR)
So, you can find the angles from here.
solar pulsar
oh okay i get it thank you, first time i did not noticed it , in my equation the angle is p\2 so the area should be p\2- 1 since the triangle's area is 1,
faint smeltBOT
@solar pulsar