#help.

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sullen gale
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PC=PD then triangle PCD isosceles
M midpoint DC then PM perpendicular on DC
OC=OD then triangle OCD is isosceles
M midpoint DC then MO perpendicular on DC
so P-M-O are colliniars
PCDO inscriptible
here i get stuck

crystal saddleBOT
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sullen gale
slender umbra
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so you're right for the part youve done

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PC = PD , and this is because they are tangents from the same external point P

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M is the midpoint of CD. So, CM = DM, making you right on that too.

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Since O is the center of the circle, MO is the perpendicular bisector of CD. That's also right.

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You didn't mention that from the symmetry of triangle OCM and triangle ODM, angle OCM = angle ODM.

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why is triangle OAM is congruent to triangle OBM?

manic comet
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there isn't proof DB is a diameter i think, but i doubt it even matters

proper impBOT
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@sullen gale

<:HelpIcon:1304095958283321385>| Help Reminder

Hello antoniobeluga, this is a friendly reminder that your help request has been inactive for more than 24 hours. If you no longer need assistance, please consider closing the thread using the +close command. This thread will be automatically closed in 3 days if it remains inactive.

sullen gale
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.close

half flaxBOT
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Unable to parse the channel name

dull sandal
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@sullen gale

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it's +close

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read the message too

sullen gale
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yes

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i did it

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tysm

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+close

proper impBOT
# sullen gale +close
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