#Parameters
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They're asking us to find all values of m for which
That equation has 2 different, positive roots x1 and x2
And they have to be this
This is what I've done
Have you tried solving the quadratic equation?
Why didn't you finish the discriminant calculation?
The one on the bottom? It just says m is all real numbers I assumed that's wrong ๐ญ
Or at least unimportant
Or um
You can simplify the discriminant more. I'd solve the quadratic
Sorry what's a discriminant?
The thing inside the square root
Oh but where is that in all of this?
The thing you're saying it has to be > 0
Is what is inside the square root
Second line
Oh well won't it just come out to be 36 > 0? Or did I do something wrong
Exactly
That means just means there are always 2 unique solutions
Now to know the solutions, you have to solve the quadratic
Which oneeee
I've got this from the bottom one
Ooh I think I know what I might've done wrong
No never mind I don't ๐ญ
Yes
Shouldn't the m^2 be positive and the m negative?
Oh yes ๐ญ
Okay I'll work from here ty
No problem
But also don't we have to
Make sure the roots are positive?
I don't know how to account for that part
Are they asking for the roots to be positive?
Yes
I'd just calculate the roots then
But how if we don't know the m
You can use the quadratic equation
And substitude b = (2-4m)
And c = (m^2-m-2)
I'm trying to think of another way of making sure the roots are positive
Viete's formulas?
This is just like
The regular delta and finding roots thing
I think this would be betterrr
Yeah
You need to know if the roots are positive
So you need to know the roots
It simplifies quite nicely
Oh it does
?
I'd rather do the viete thing thoughh ๐ญ
It looks so simple
If I wrote it down correctly
Yeah that's correct
Okayy goodd
Yeah that'd work. If they're both positive, then their product has to be positive
And their sum has to be positive
You gotta solve those equations, then
Yes I've just finished
Sooo adding all those groups together and the previous one
That's the answerr?
Wait wait, here you simplified the m^2 but they don't simplify, do they?
Nahhh I just solved it too so I can see if the equations are the same or not haha
That's great help omg
That's what I got heree
-4m -2(-m) = -2m, not 2m
Nahh algebra is so annoying
YEAH
There's also one other thing
Here, you need both things to be true
So the first one is telling you
m in (-infty, -1) u (2, +infty)
And the second one is telling you
m in (-0.5, +infty)
You have to get the interval where both are true
Good?
Yeee
So now you need to find both things to be true
Final result
Does > mean it is included and ( means it is not included?
Yes
Yeee it's great then
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