#Measurability of sup of measurable functions

30 messages · Page 1 of 1 (latest)

potent summit
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I don't understand this step in a proof in Adult Rudin, Theorem 1.14.

Let $X$ be a topological space and let $f_n: X \to [-\infty,\infty], n = 1,2,3,\ldots$ be a sequence of measurable functions.
Rudin proves that $g = \underset{n \ge 1}{\sup} \ f_n$ is measurable.
The proof uses:
$$g^{-1}((\alpha,\infty]) = \bigcup_{n=1}^{\infty} {f_n}^{-1} ((\alpha,\infty])$$ for all $\alpha \in \mathbb R$, why does this equality hold?

uncut ridgeBOT
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pseudo lichenBOT
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gfauxpas

visual spire
pseudo lichenBOT
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Omegabet_

visual spire
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$g^{-1}((\alpha,\infty])={x\in X|g(x)>\alpha}={x|\sup_n{f_n(x)}>\alpha}$

pseudo lichenBOT
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Omegabet_

visual spire
potent summit
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ah, thank you!

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The top voted answer seems to have a mistake of confusing the definition of lim sup with sup, but I should be able to derive the correct answer from it

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oh wait no, I'm wrong, the answer is correct

potent summit
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@visual spire how do I award you points?

visual spire
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I think just say thanks?

potent summit
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thanks!

ivory rapids
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you can thank them, and then click the red button to close the post

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The rep bot is permanently down to prevent abuse, so it does not react to the keyword "thanks" anymore

potent summit
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@ivory rapids didn't work

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no red button or prompt

ivory rapids
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Ok now that is just weird

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the +close command does not work?

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It seemed to work for me

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@potent summit

potent summit
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oh I was using the hotdog button close

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+close

gleaming gulchBOT
# potent summit +close
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gleaming gulchBOT
# gleaming gulch

Thank you for your feedback! Omegabet_ has been awarded 1 helper_points. They now have 822 helper_points. They have 3 helper_points daily left for today.

ivory rapids
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now the red button will close the post