p(x) 2x^3 + ax^2 + bx -2 divided by x+3, remainder is -50
the factor is 2
the value of a+b is
#polynom
strong flame
limber pythonBOT
p(x) 2x^3 + ax^2 + bx -2 divided by x+3, remainder is -50
the factor is 2
the v...
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strong flame
p(-3) = -3a-b = 2
p(2) = 2a+b = -7
a = 5
b = -17
but apparantly it's wrong because
a. 10
b. 4
c .-6
d. -11
e. -26
5 - 17 = -12
icy wadi
p(x) 2x^3 + ax^2 + bx -2 divided by x+3, remainder is -50
the factor is 2
the v...
i hope you used the remainder theorem?
also, show your work so i can get a clearer picture of what’s going on
also, what does “the factor is 2” mean?
strong flame
factor is (x-2)
strong flame
i hope you used the remainder theorem?
which one
icy wadi
you mean, a different factor of the same polynomial
icy wadi
factor is (x-2)
okay
strong flame
there's js 1 factor
my work:
p(-3) = -3a-b = 2
p(2) = 2a+b = -7
a = 5
b = -17
that's it
icy wadi
which one
the one that states the remainder of division for a factor (x-c) is equal to p(c) where p is the given polynomial
icy wadi
so you’re saying that -54+9a-3b-2=-50, but where did the f(2) part come from?
icy wadi
what?
icy wadi
idk what i'm doing
if you don’t, either revisit it or take a break
it’s a bit clearer for me now, i guess.
f(2)=0 since it is a factor.
strong flame
if you don’t, either revisit it or take a break
revisit?
no bro i'm trying to understand math
strong flame
f(2)=0 since it is a factor.
ohhhhhhhh
icy wadi
ohhhhhhhh
so how did you calculate those formulae originally if you were confused on what you were doing?
strong flame
js trying random things
icy wadi
don’t...do that
strong flame
that's me rn
icy wadi
anyways, yes
strong flame
my work:
p(-3) = -3a-b = 2
p(2) = 2a+b = -7
a = 5
b = -17
.
icy wadi
yeah.
strong flame
yeah..
icy wadi
just wanted to make sure you understand what you were doing since you were confused
strong flame
okayy
i understand the f(2) thingy
like
how to put the numbers in
but idk what to do next
icy wadi
so you’re saying that -54+9a-3b-2=-50, but where did the f(2) part come from?
use this, i know what you did wrong
icy wadi
let me see.
strong flame
don't mind the 9a² it's supposed to be 9a
icy wadi
don't mind the 9a² it's supposed to be 9a
is your work on the left or right side?
midnight compassBOT
dark matter
strong flame
yes
OOOOOOOOOOOOPSSSSSSSSS
i was so sleepy yest i had been up since 3 am and i was doing it at 4pm
i forgot it's ² and not ³
strong flame
hey can u help me on this @icy wadi
icy wadi
hey can u help me on this <@1245133657690214403>
i went to sleep, sorry.
strong flame
i went to sleep, sorry.
that's fine, i still don't know the right answer tho
icy wadi
that's fine, i still don't know the right answer tho
okay.
for a cubic in the form f(x)=(x-a)^3+b we have that (a,b) is the inflection point of the graph
try to associate it with what you have
onyx wedgeBOT
@strong flame