#i just cant seem to understand it im getting annoyed test in 2 days
umbral talon
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umbral talon
yeah
ivory yew
we want it in the form (3x+a)(x+b), where a and b are to be determined
umbral talon
yes
ivory yew
we know that ab=-30 and a+3b=13 from the equation given
so find 2 numbers that satisfy this.
umbral talon
dont that mean the only possible answers are factors of -30
ivory yew
dont that mean the only possible answers are factors of -30
yes.
umbral talon
so
6,5 2,15 1,30
and just add - infront of one of them
3, 10
ab=-30 and a+3b=13
5 and -6?
umbral talon
wdym
cos 5 x -6 = -30
and 5 + 3(-6) = 5 - 18
ohhh
so 6 x -5 = -30
6 + 3(-5) = 6 + -15
yo i still dont get it ngl smh
yo i get it now i thikn
-5 x 6 = -30
-5 + 18 = 13
trail field
start by putting in a (x+a) (x+b) format
then find out what to add/multiply to have one of them as zero
umbral talon
im gonna use what the other guy said cos its the only tihng i've understood for the past 2 hours
thanks to you guys tho
ivory yew
already flopped the last one
good luck!
but yes, i would like to propose an alternate method here
umbral talon
is there an easier way
umbral talon
for some reason this just seems harder
umbral talon
are you allowed calculators
nah its non calc
ivory yew
is there an easier way
yes
what you can do here is take, for a quadratic ax^2+bx+c=0, the a term onto the c term, i.e. transform it into x^2+bx+ca=0.
so in this example, we would have y^2-11y-60=0
ivory yew
so then you have to find factors of -60?
use a normal method, yes.
here, ill give an example
lets say we have 2x^2-3x+1=0
umbral talon
yeah
umbral talon
yh
ivory yew
we solve x^2-3x+2=0
so (x-2)(x-1)=0
now we have to "add" a 2 to make the leading coefficient satisfy such
you can do it in some fashion
because 2x^2-3x+1=(2x-1)(x-1)
umbral talon
ngl im not understanding this
ivory yew
if my first method works for you, go for it
its a little bit complicated with non-prime leading coefficients, but i have one more method.
let’s take our example 2x^2-3x+1=0
we can split the middle by calculating the numbers that multiply to 2 and add to -3
so we get that 2x^2-2x-x+1=0
then 2x(x-1)-(x-1)=0
we factor out the (x-1) and get that (2x-1)(x-1)=0
let that sink in for a bit @umbral talon
umbral talon
i think thats what i learned in school
fuck man this is what happens when u dont focuse in maths for the past month
ivory yew
i think thats what i learned in school
this is the optimal method because it works for all types
umbral talon
man this just feels too hard to understand
a good 2-3 hours i've been trying to understand
im atually getting frustrated aswell
maths used to be one of my best topics aswell which makes me even more mad man
umbral talon
this is the optimal method because it works for all types
yo i kinda got it
Look at question 2 did I do it right?
ivory yew
Look at question 2 did I do it right?
👍
umbral talon
actually thank you so much
cos without u i dont think i was sleeping tonight lmao
ivory yew
cos without u i dont think i was sleeping tonight lmao
lol
ivory yew
this is correct as well
warped bloomBOT
@umbral talon