#I urgently need an answer to all this:
28 messages · Page 1 of 1 (latest)
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Uh let's start with domain
I figure the domain here should be pretty obvious just take note that the denominator cannot equal
Next intersections with the coordinate axes
Finding the intersection with the y axis should be trivial
Just substitute x=0
D(y): x≠-1?
Mhm
For the intercepts with the x axes I think you can simply solve for (x+3)^2=0 if I'm not mistaken
Should apply unless one of the solutions is equal to -1
In that case you need to get rid of that one
But here we're good
@brave yoke so with that info can you find the coordinate axes intercept
Or do you still need some help
For 3.) the answer should be obvious as it's squared
So you use geogebra to make a graph
Now if you are in China or India than you might not be able to use calculators
Let's go with the first question
Hint 1. You that x/0 is forbidden so put that in mind and write the domain. For example x can't be -1 otherwise the whole thing will end
Therefore the domain is all natural numbers except minus 1.
Hint 2. coordinate axes are in finite numbers for functions that are not like sine , cosine and stuff like that. Apply easy x value 0 and you will find the intersect.
Hint 3. Now talking about making the graph, make a table of values for x and for which the values of y will appear
@brave yoke
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