#Area of polar coordinate
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they just did it in degrees, is all.
and besides, both graphs have different points where the radius is equal to zero
if you solve 2cos(3x)=0 and sin(2x)=0 you get completely different answers.
try it
Ok what about something like this
I still put r=0 to find the bounds
?
For anything that’s adding/subtracting
yes, to find where you partition the integral.
if you could give context that would be nice
@limber prawn
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