#help with trig graph question need help NOW!!!

45 messages · Page 1 of 1 (latest)

gaunt echo
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when a pendulum 0.5 m long swings back and forth, its angular displacement theta from the rest position, in radians, is given by theta(t) = 1/4sin(pi/2(t)). where t the the time in seconds. at what time(s) during the first 4s is the pendulum displaced 1cm vertically above its rest position? (assume the rest position at t=0)

autumn tartanBOT
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kind stag
gaunt echo
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no please i need help

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i drew a graph but it didnt help

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the period of the sin graph is 4

kind stag
gaunt echo
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yes

kind stag
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and just to make sure, we are dealing with $\theta(t)=\frac{1}{4}\sin(\frac{\pi}{2}t)$, right?

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or is the t on top?

gaunt echo
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t on top

kind stag
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okay

storm onyxBOT
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dark matter

kind stag
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perfect.

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so yes, the period is 4

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what else can we note?

gaunt echo
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the max is 0.25 and the min is -0.25???

kind stag
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yes

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hmm.

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we would have to make a function in x(theta) to determine the angle at which it is 0.1 cm above the rest position.

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any thoughts?

gaunt echo
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why 0.1cm? it says displaced 1cm vertically above its rest position

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are you converting to meters if so it would be 0.01m

kind stag
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misread, sorry.

gaunt echo
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its ok

kind stag
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so the pendulum is at its rest position for t=2k seconds where k is an integer

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but we only consider t<=4 so at t=0,2,4

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and at t=0 the angle of the pendulum is 0

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the problem is where the rest position is relative to.

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i would assume at the minimum.

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so for t=0 the pendulum is at the minimal position

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is this a good assumption?

gaunt echo
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i dont understand what u mean

flat saddle
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He's saying initially the pendulum would be where the ball attached by a dotted line would be

kind stag
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my phone is crashing

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aaaaaaa

gaunt echo
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oh

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i need to use a sin graph to solve this not those pendulum diagrams thingies and i was never taught how to use them

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so on a test i cant use them

honest marlinBOT
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@gaunt echo

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gaunt echo
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+close

honest marlinBOT
# gaunt echo +close
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