#I have 19 min left just need answer
25 messages · Page 1 of 1 (latest)
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just remember x^2n and x is negative then x^2n is positive if n is integer.
x^(2n-1) and x is negative then x^(2n-1) is negative if n is integer.
(-x) * (-x) * x = x^2 * x = x^3
(-x) * (-x) * (-x) = (-x)^3
i can't read the questions fully its not clear
but i think this info is enough to solve it all
just put in values like
y = -2
y^3 = (-2)^3 = (-1) * 2^3
I need answer for 10 11 12 13 14 1l16 17 18 19 and 20
just type out the questions
Just count the letters and write the number of letters in the power
xxx has 3 xes so x^3
HUH?
thats rude
Im sorry
BRO I WAS GONE FOR 3 WEEKS
Ok ok
I WENT ON USA VACATUON
I was never qualified to be a teacher i cant help you
😐
just consider
x* x* x = x^3
x * x = x^2
You see pattern
x* x^2 = x^3
x^n * x^m = x^(n+m)
Now x * y * x * y just count number of x and y. There is 2 x and 2 y here
So x^2 * y^2 = x * y * x * y
@violet folio
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