#GEOMETRY
60 messages · Page 1 of 1 (latest)
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I suppose you have the original question, considering that i’ve seen this multiple times already
i found it on telegram
and also, try to use pythagorean theorem here
consider that the base hexagon has some sort of line perpendicular to the height
yeah, k would be your slant height here
i’ll try to fetch a picture
ok, i have an attempt at a solution
try to use the law of cosines to find k
if you could find the original diagram (i need to eat right now) that would be appreciated
got it one sec ill have a look around and get back to you
okay
heyy i asked that person to send a picture or smtg and they sent me this 
i’m back
sorry for the long wait
i was eating with family
yes that looks accurate
basically what i found was that the area ratio is 1:2
so the truncated part of the pyramid actually had a triangle of area 1 on it
and i calculated the value of the height of the big triangle
no worries
then i used similar triangles (the side length ratio is 1:sqrt(2)) to deduce that the slant height could be found
hmmm
it’s straightforward
i see ill try that
yep it’s pretty easy lol
ill retry it as well i did it prtty quick
could you also show the calculations for it?
i got 1.3103, to 4 sig figs
thats the expression i got
i got that as well at first but that wasnt rightt T_T
how
i got 1.134
is this method wrong ?
im not getting the asnwer
can anybody tell me if the method si wrong
send the exact value
what was it
1.137
oh
can you send the exact value
SMAE I FORGOT IT AS WELL
+close to close the post if you have no further questions
got it