#largest integer
65 messages · Page 1 of 1 (latest)
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How do we determine all of those measurements?
...and what is "the average"?
mean
then median is average of 1012th and 1013th number
i think those both need to be 2024 to satisfy it being an integer
am I correct?
difference between smallest and largest number is 2024 so thats the range as well
and the mode is 2024 as we know
my computation got 3036 but its appearently wrong
...how do you calculate it?
add up all the numbers and divide by the amount of them
oh wow im a dumbass
Right.
i mean i do have the equation max = min + 2024 right
This here is the most important bit.
This gives us an upper bound on the max.
We know the set contains the number 2024, therefore the greatest the minimum can be is 2024, therefore the greatest the maximum can be is 2024 + 2024 = 4048.
Now, can the maximum actually be 4048?
no
Why not?
well because the minimum and maximum would be equal
i think the maximum possible is 4047
...what?
4048 = 2024?
Because 4048 is the maximum of a set with minimum and range 2024.
What's the mode?
i mean its 2024 but if you include 4048 you would need to include additional non-2024 numbers
What is the definition of the mode?
most common number
So then the mode doesn't affect anything.
Because we can have literally 2023 2024s.
This is why I asked you what all those words mean.
I was asking you to define them.
Because that's the first step to using them to actually reason about the dataset.
so how do i solve this
...start... by defining... "mean", "median", "mode", and "range".
Specifically in terms of how they are calculated.
i did
So. We know that the range is 2024.
We know that the range is the difference between the max and min.
Therefore, we know max = 2024 + min.
Therefore the max of the max is 2024 + 2024 = 4048.
Can the max actually be 4048?
Prove it.
basically its a task based on inputing correct solution lol
No.
I just needed to fix 1 of my equations though
What equations?
@open holly
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