#Need help on derivative applications
54 messages · Page 1 of 1 (latest)
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here, you’re meant to find dV/dt, and you’re given dh/dt and V
set up an equation for V first.
to be precise, use the volume of a cone formula, then since you’re given V, dh/dt, and and r (since it isosceles) we can use the formula
V = ⅓•pi•r²h
then?
how to take derivative cuz there are 2 variables r and h
So then you have to find one as a function of the other.
r as a function of h?
That would make sense, given you know dh/dt.
but how
...use the information you're given.
how to find their relation
what information have you been given?
right-isosceles shaped cone tank
Okay.
peak vertex at right angle
So how do we use that?
i have trouble visualizing it
You know what a right isosceles triangle is, right?
yea
It's the 45-45-90 triangle.
I'm not sure how that proves what you're saying.
what?
i divide the triangle into 2
then become 2 smaller isosceles right triangles
Why?
wdym why
(also, just as a side note, please be clearer with your wording, it helps the helper to understand your reasoning)
I mean, why does that happen?
similarity maybe?
You shouldn't use "maybe" in math.
i mean
its isosceles
so the height divides the triangle into 2
the base
and the 90 angle
so the smaller triangles r also isosceles
You're not communicating an actual chain of logic, just a series of disjointed unconnected ideas.
@finite belfry
@finite belfry
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