#how do i solve this i got math exam soon
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hi
oh this is just rationalization
you have to make the denominator a rational numbers
i suppose youre familiar with the notion of rationals and irrationals?
YESS but i kinda dont understand it
wdym
this particular thing?
its just tryna make the denominator of a fraction Rational
by whatever means possible (and efficient)
I guess maths is difficult for me cause i hate it sm its so boring
i dont understand why i need this in the future
its not even important
NO STOP
I NEED TO GET 100%
I ALREADY UNDERSTAND THE OTHER PARTS OF THE EXAM, ITS JUST THIS ONE THING
Basically when you rationalising the denominator
Let's say our denominator is sqrt(3)
We just multiply the denominator and numerator by the sqrt(3)
Such that the denominator is 3
@midnight quarry
THANK YOU
IK THIS
BUT LIKE
omg idk how to explain in english sorry im germanš
okay
$\frac{7}{\sqrt{5}}$
Muus
Rationalise
Uh no
I don't want the decimal estimation
I want the rationalised form
The topic which you've literally asked to cover
I DONT UNDERSTAND IT THATS THE THING
bro am hopeless when it comes to maths
Oh so
You don't understand
What the question be asking
Yes
rationalise means to make the denominator of a surd rational
I mean not a formal definition
But for now let's take it as that
Do you know what a rational number is
yes i know that
If it isn't a perfect square inside that sqrt
Then it's irrational
At least for the positive integers
Ok
So now that we've covered that
Let's say we had a fraction
$\frac{1}{\sqrt{2}}$
Muus
How can we make the denominator of this fraction rational
The numerator can become irrational
All that matters is that the denominator becomes rational
Recall
$(\sqrt{a})^2=a$
Muus
uhh
wait wait wait
yes i remember this
whenever the 2 is there
the number stays the same
Thats definitely one way of remembering it
we call that small 2 hochzahl in german
if im honest noš
Is 2 a rational number?
yeah sure
.
What
it is of thr form p/q where q isnt 0. and p and q are coprimes
I think you might need to do some revision
šš
whats thr probelm u r getting
we might have a work around
Nah like bro's being asked to rationalise surds
But like
Bro does not know what rational means
I DOTN GET THIS BRO
aaah too many colour's
this neither..
UR RIGHT I DONT
idek what reellen is bro whats a reellen number
Alright
Let's go over some definitions
I'll just use some layman terms
A rational number is a number that can be expressed in the form p/q where p and q are integers
what is p/q in german term
I mean do they have to be coprime @autumn lantern
rational number is a number that can be expressed as p/q where in the simplest form p and q are coprimes and q is not 0
in simplest form, yes.
Ah simplest form
how r u both so smart
Well i think we can cut the coprime part
om pg bro
actually it's basically cuz of age difference
Yea
how old r u
16
15
OKAY IM 15 TOO.
i almost completed hs.
Anyways
A rational number is a number that can be expressed in the form p/q where p and q are integers
and qā 0 for obv reasons
Well whole numbers are the set of non negative integers
Integers include like -5,6,7
Negatives and positives
Ohh
0,2,4,6
those are
straight numbers?š
idk what yall call them in english
and "unstraight" numbers are numbers like 1,3,5,7
Even numbers
And odd number
German terminology is crazy
whatever its called
basicallt rational numbers are numbers that can be expressed in thr form of p/q
whete p and w are normal positive and negative integers
like -1,-2 -3,-4 and 1,2,3,4 but not 0
OHHH
rationalising focuses on making the denominator rational
no
ITS NOT RIGHT?
no its not right
It's not a calculation it's more of like reforming the expression
Your objective is simply to make the denominator of the expression rational and simplify as best as possible from there
From example let's say I have
$\frac{1}{\sqrt{2}}$
Muus
To rationalise I simply re express the fraction with a rational denominator by multiplying the numerator and denominator by sqrt(2)
$\frac{1}{\sqrt{2}}=\frac{1\cdot\sqrt{2}}{\sqrt{2}\cdot\sqrt{2}}\newline = \frac{\sqrt{2}}{2}$
Muus
is help still needed?
what the hell
yes pls
do you understand the basics?
yes
okay, iām going to let you try a tougher problem
no.
omg
UM YES I DO
rationalize $\frac{\sqrt{2}}{\sqrt{3}-\sqrt{2}}$
dark matter
as per me what they are considering basics is not same as ur basic
Ohh
my basics is over one singular root.
oh okay
like what denzio provided
yeah then they r not confused
this is a bit tougher
i remember when it was lockdown i bunked classes and a similar problem fucked me
i will have to introduce the concept of conjugate for this if you donāt understand
the thing is i need an explanation on how to do it
alright, great
u need to focus on making the denominator devoid of any underroots
so, letās call an irrational number $\sqrt{a}+\sqrt{b}$
dark matter
itās conjugate is denoted by $\sqrt{a}-\sqrt{b}$
dark matter
pls reply with "yes" or "i understand" after every step, that helps a lot
okay i know this one
alright i will
this is the key here.
letās say weāre given a fraction $\frac{1}{\sqrt{a}+\sqrt{b}}$
dark matter
what we want to do, to rid the denominator of irrational numbers, is multiply by $\frac{\sqrt{a}-\sqrt{b}}{\sqrt{a}-\sqrt{b}}$
dark matter
this is obviously equivalent to 1.
@molten blaze sry to interupt but
?
can you vc?
isnt conjugate numbers, numbers having reciprocal equality with one another
maybe, but not right now
i think its easier when you explain it in vc
iāll try, then.
itās not guaranteed, though
or is it related by any kind of transformation?
in this case, iām defining it similar to a complex conjugate
oh
i just like to call them that way, itās easier for my mind and probably most other people
anyway iāll try to explain it here
They do call it conjugates in my country too
now one more key thing is to note that $(a+b)(a-b)=a^2-b^2$
dark matter
so now, letās put this all together
is this right?
we have $\frac{1}{\sqrt{a}+\sqrt{b}}\cdot\frac{\sqrt{a}-\sqrt{b}}{\sqrt{a}-\sqrt{b}}$
dark matter
no
HUHHH
you got the right answer but have the wrong working.
youāre supposed to be multiplying using $\frac{\sqrt[3]{a^2}}{\sqrt[3]{a^2}}$
is it righr
i doubt it
dark matter
small 2 thing at the right top
no.
you fraction ends up being cbrt(a), which is not one
if i were your teacher i would not give you full marks for that
š¢
my teacher takes off half a point if i get it kinda wrong
each step is evaluated
yeah, but conceptually itās not clicking in your head
thatās where the marks are taken off
you have to make sure youāre multiplying by one
u can modify the expression by multiplying and dividing tje same thing. u cant jusr change somethings value
from here we get that this is equal to $\frac{\sqrt{a}-\sqrt{b}}{a-b}$ because of the difference of squares mentioned earlier
dark matter
english maths is so hard oh my goddd
different terminology makes stuff hard
im extremely used to german
and i am very skeptical of each and every word because the exam i focused towards gets u using english
every word written in a question could make a difference
yes
Dang do you not have a notebook appš
i do
Rationalising the denominator should be fairly obvious in this one
i asked my dad for help but he said i should watch videos on youtubeš¢
Just ignore the numerator when coming up with the fraction equivalent to 1 to multiply by
but then he scolds me if i get a bad grade on my exam
i think i know how to solve that
do the same thing u did earlier
there is only one term in tje denominator
okay wait
This thread is being closed automatically as the starter message was deleted.
@midnight quarry
aa
Alright but please don't delete the starter message
anyways.
Okayyyy
i think i understood it sm better now
Also, I am not sure that we will be able to close it properly afterwards
So ping me if we can't, I might have to delete this post
I hope you understand
Its alright thank you
okay, can you try the example problem?
š
What was it again?
wb this @molten blaze @autumn lantern
u just dont wanna understand
ur method is correct
sry mb
the third one is wrong
No its alright
also write the multiplication sign in places u need it. u put = everywhere
even in places of multiplication sign
GGS
Atb