#Can someone help for part a (roots of polynomial)
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Can someone help for part a (roots of polynomial)
well, what do you think the roots are?
in order for it to be an integer?
well, what is the conjugate?
so, use polynomial division.
or, better yet, solve the a+13/a+46 since you know what a is
I cant use polynomial division with this
And when u solve a +13/a+46
You get alpha = 3 plusorminus 2i
you got two roots
divide polynomially from there
alpha is one of them
bets is another
gamma would be found by dividing
I dont think this question wants me to polynkmial division
i see
ur prolly right
i dont wanna try anything because the last root, a + 13/a +46 is smth i havent done in a while or it just looks like smth else
Nvm i got it
If i sub 3+2i and 3-2i into a+13/a +46
You get 52
For both
So alpha = 3-2i , 3+2i and 52
sounds good
this doesn’t feel right at all...
are you sure you solved for a correctly?
Yh
Thanks
the polynomial to solve should be $a^2-6a+13=0$
dark matter
huh.
Yh
this question feels off.
Yh i get what u mean
the other root should be 52=13(gamma)
Wdym
do vieta's again.
I would still get the same answer
whats vietas
is that vietas
i see
Isn't it the product
multiplied, here.
yea
Sorry the products
sigma a = -b/a
Alpha times beta times gamma
well, we have our two roots
so what about the third?
i dont think it would produce the correct answer, though.
i assume you know that the roots of the polynomial multiply to 52?
How
@ocean sonnet
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