#help with number 13
167 messages · Page 1 of 1 (latest)
- Do not ping the Moderators, unless someone is breaking the rules.
- Do not ping the Helper Moderators, unless there is a conflict between helpers.
- Do not ping other members randomly for help.
- Ask your question and show the work you've done so far. If you've posted a screenshot of a question, specify which part you need help with.
- Wait patiently for a helper to come along.
- If the Helper has answered your question, remember to thank them with the Mathematics Ranks bot and close the thread with:
+close
Feel free to nominate the person for helper of the week in #helper-nominations
If you're happy with the help you got here, and the server overall, you can contribute financially as well:
there’s an answer key if anyone needs it but here’s what i know so far
-
the problem represents a limit of the function f(x)
-
the function f(x) is somewhere in the brackets
-
C is a number that i need to plug in for f(x)
what i DONT know:
- what formula they’re using. i thought this was f(x+h) - f(x) all over h
it’s in the form $\lim_{h\to 0} \frac{f(x+h)-f(x)}{h}$
flying green people eater
well that answers one of my questions 😂
okay so basically they replaced h with delta x?
yep
alright i didn’t finish my “idk” section so i’ll just tell u straight up. i’m not sure what the -14 outside of the brackets represents
it represents f(x).
or, in this case, f(c).
does that mean the result of c being plugged into the function?
am i just supposed to know that? it’s not in the original limit notation that you specified
and $f(x+{\delta}x)$ is clearly shown on the left hand side of the numerator
flying green people eater
lowk this sounded rude that’s not how i meant it
well, i just replaced x with c.
it’s not rude it’s a genuine question lol.
no i mean like how am i supposed to know that the -(-14) is supposed to be there or more accurately - what part of the limit notation does that belong to
(you must be on unit 3, right?)
uh unit 2
idk maybe we’re behind
lol my school is pretty below average so i’m not surprised
sep 4?
smth like that
i cant really specify this more than i said earlier
it just represents f(c)
so are the brackets in my original picture all just f(x+h)?
tbf, i’m in an accelerated program and in calc bc, so i’m not surprised either
oh we’re on ab
yes, that jumbled mess is f(x+h)
lol
not really. i would say that the whole brackets are f(x)
but the answer key doesn’t agree
(just to let you know, delta x notation is outdated, the more modern notation used h)
hmm, let me see.
i’m well aware… a diff teacher told me that my current teacher is teaching us outdated stuff 🤦♂️
f(x) = 2x^3 - 2x - 2
which is correct.
ah well i don’t know which numbers are supposed to be together
maybe, for example idk how we got 2x^3
does the 2 come from the two outside the first parentheses
yes.
and what about the x?
it’s $f(x+\Delta x)$, after all.
flying green people eater
stupid phone.
the x?
i don’t understand
2x^3 where does the x come from because if it were me i’d say that it’s 2^3
oh, sorry, i do now.
it’s because we are trying to find f(x).
and the expression given is $2(-2+\Delta x)^3$
flying green people eater
nooooooo
so where does it come from?
here, i’ll try to give an example
let’s say we have $\lim_{h\to 0} \frac{[(1+h)^3-1]-(0)}{h}$
flying green people eater
from here, we know $f(1+h)=(1+h)^3-1$
flying green people eater
ugh, this stupid phone.
we just let x=1+h.
literally as simple as that.
okay so then f(x) would be 1+h?
no.
wait no( 1+h)^3?
ah, close.
remember, x=1+h.
wherever you see a 1+h, you have to replace it with an x.
no.
wtf
you get one more try, and i’ll give the solution.
alrifhty
think about it.
damnit
f(x)=x^3-1.
okay.
oh nvm i WAS going to say that
i forgot about the -1 🤦♂️
wtf i think this makes perfect sense
could u give me another example?
okay, this’ll be a bit harder.
$\lim_{h\to 0} \frac{[2(2+h)^2-3(2+h)+1]-(3)}{h}$
no hints, nothing.
2x^2 -3x + 1?
good!
😎
flying green people eater
2
icl i cheated though. i just looked at the first number in both parenthesis. is there a proper method?
no, that’s completely valid, lol
any idea why he says both are x+h? i thought the notation was f(x+h) ONCE
wdym "both"
you see the two red arrows that point to both parenthesis and say x + h
in the original notation f(x+h) they only use f(x+h) once
but in this problem
it’s used twice
yes.
is this really the same as f(x+h)-f(x)/h?
because they both represent x+h
yeah but why twice and why subtract? there’s no notation that says use x+h twice and subtract from them
you're not subtracting
its just f(x+h).
why does it say -2 before the second parenthesis then?
if not subtracting then where does the negative come from
-2 is part of f(x).
i’m so cooked
then why isn’t there a negative two for the other one
the other “2” outside the first set of parenthesis
is this question deliberately deceptive
no.
its because its f(-2).
?
i was wrong
but i’m still confused
are you looking at the -2 inside the function
i’m looking at the one outside of if
it
this is what i expect it to look like when comparing to the correct notation
it’s painfully obvious that the first fraction is x+h
and the - 1
is - f(x)
and it’s all over h
but with the question i’ve showed you i don’t know why -2(-2+deltax)-2 is there
alright.
f(x)=2x^3-2x-2
f(x+h)=2(x+h)^3-2(x+h)-2
+close
Please thank the helpers who assisted you by clicking the buttons below. You can thank each helper only once. Once you're done, click "Close Post" to close this thread.