#Please help me with my exercise

50 messages · Page 1 of 1 (latest)

night umbra
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Given triangle ABC. Construct a circle (J) passing through A and having B as point of tangency, a circle (K) passing through B and having C as point of tangency. (J) intersects (K) at P . Prove that (PCA) has A as point of tangency.

blazing impBOT
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dusty pond
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like it intersects AB...

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so yea thats all..or prob ur q is unclear

night umbra
# high ingot This feels poorly translated.

Given triangle ABC. Construct a circle (J) passing through A and having B as tangential point, a circle (K) passing through B and having C as tangential point. (J) intersects (K) at P . Prove that (PCA) has A as tangential point.

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@high ingot Is this more clear?

high ingot
high ingot
rustic geode
teal agate
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"Point at which this line is tangent to the curve"

night umbra
rustic geode
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what angle does a tangent line make with a circle?

high ingot
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That is, the two curves have the same "immediate slope".

night umbra
rustic geode
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thats really what a "point of tangency is"

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the point on the tangent line where it touches the circle

night umbra
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@high ingot @teal agate @rustic geode Thank you for helping me understand the concept and the correct spelling of that

desert jungleBOT
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@night umbra has given 1 rep to @rustic geode @high ingot @teal agate

high ingot
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Or... something like that. It's not entirely clear from the way you said it which lines the circles are supposed to be tangent to.

night umbra
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we only have (J) is tangent to AC at A, (K) is tangent to BC at C and (J) intersects (K) at P

high ingot
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Right. Because it can't be tangent to AC since it passes through both A and C, and it can't be tangent to BC at A.

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Hmm. How many circles are there that pass through B and are tangent to AC at A?

high ingot
night umbra
high ingot
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No, I meant (J).

night umbra
high ingot
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...no?

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I'm confused.

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Post the original question.

night umbra
high ingot
night umbra
high ingot
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Give a translation after.

night umbra
# high ingot Give a translation after.

Datis triangulo ABC. (J) transit per A, B ut JB sit perpendicularis ad BC in B, (K) transit per B, C, ut sit KC perpendicularis in AC in C. Proba quod CA contingens PCA in A

high ingot
night umbra
night umbra
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@high ingot

smoky crystal
modest portalBOT
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@night umbra

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