#Please help me with my exercise
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u have done it here..
like it intersects AB...
so yea thats all..or prob ur q is unclear
This feels poorly translated.
Given triangle ABC. Construct a circle (J) passing through A and having B as tangential point, a circle (K) passing through B and having C as tangential point. (J) intersects (K) at P . Prove that (PCA) has A as tangential point.
@high ingot Is this more clear?
More clear, yes, but there's no such thing as a "tangential point".
What do you think the word "tangent" means?
"point of tangency" would be more correct here
"Point at which this line is tangent to the curve"
I think the only point that a line intersects a circle?
not necessarily intersecting.
what angle does a tangent line make with a circle?
"Tangent" is an adjective describing a curve which intersects another curve at a single point where the derivatives of the two curves have the same value.
That is, the two curves have the same "immediate slope".
i think an angle = 90° made with radius and tangent line
yes
thats really what a "point of tangency is"
the point on the tangent line where it touches the circle
@high ingot @teal agate @rustic geode Thank you for helping me understand the concept and the correct spelling of that
@night umbra has given 1 rep to @rustic geode @high ingot @teal agate
So what we would actually say is that (J) is tangent to AC at A, (K) is tangent to BC at C, and (PCA) is tangent to AB at A. If you don't talk about the curve the circle is tangent to, you're not giving any information, because there's infinitely many curves which are tangent to any other curve at any given point.
Or... something like that. It's not entirely clear from the way you said it which lines the circles are supposed to be tangent to.
i mean we need to prove that (PCA) is tangent to AB at A
we only have (J) is tangent to AC at A, (K) is tangent to BC at C and (J) intersects (K) at P
Right. Because it can't be tangent to AC since it passes through both A and C, and it can't be tangent to BC at A.
Hmm. How many circles are there that pass through B and are tangent to AC at A?
i think none
...so (J) doesn't exist?
(K)
No, I meant (J).
I think it passes through A and is tangent to BC at B
but it is not in English
Does it use the Latin alphabet?
it is Vietnamese
Give a translation after.
Datis triangulo ABC. (J) transit per A, B ut JB sit perpendicularis ad BC in B, (K) transit per B, C, ut sit KC perpendicularis in AC in C. Proba quod CA contingens PCA in A
A picture of the original question.
Ok
Do you the question in Vietnamese?
@high ingot
just send a picture, we can translate accordingly
@night umbra
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