#Need Help - College Algebra
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Ive gotten this fair but i cant seem to figure out what happens next after the synthetic division
the numbers you to the left of the bar represent the coefficients of the quotient polynomial (in descending order of degree), and the number to the right is the remainder
could you please explain that a little better, still a bit confused
sure, when you divide a polynomial by a linear factor, the degree of the quotient is reduced by one, relative to the original polynomial. so the coefficient furthest to the left of the bar will be the coefficient of the x^3 term
because the original polynomial is of degree 4
so you have 2x^3 as the first term of the quotient
ok ok
likewise, the next number is going to be the coefficient of the x^2 term, and so on
down to the x^0 term
or constant term, if you will
oh so turn the bottom answers into a equation pretty much
the number to the right of the bar will be the remainder 
like 2x^3-1x^2+3x-11
the bottom numbers are the coefficients of the quotient yes
exactly!
ohhhhh ok
oh ok
the remainder of the division is 25 
the standard way to write it is as follows:
$$p(x) = Q(x) q(x) + R(x)$$
higher!
hmm ok
where p(x) is the dividend, q(x) is the divisor, Q(x) is the quotient, and R(x) is the remainder
can you give me aexample using random numbers cause thats kind of confusing. 
notice that if R(x) = 0, then this just becomes p(x) = Q(x) q(x), or p(x)/q(x) = Q(x)!
ok ok
I shall steal one from the internet
bet
p(x) = x^4 + x^3 + x^2 + x + 1
q(x) = x^2 - 1
Q(x) = x^2 + x + 2
R(x) = 2x + 3
ok ok
then x^4 + x^3 + x^2 + x + 1 = (x^2 + x + 2)(x^2 - 1) + (2x + 3)
this is the form p(x) = Q(x)q(x) + R(x)
you can expand the RHS to confirm this for yourself 
alright bet, i think i got it now

Preciate the help. 
no worries, you may close the channel if you have no more questions 