binomial expansion + 3 unknown simultaneous equation | Mathematics | Page 1

keen bison Nov 1, 2024, 5:23 PM

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i have found the equations but idk what to do from there

valid tideBOT Nov 1, 2024, 5:23 PM

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keen bison i have found the equations but idk what to do from there

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dusky apex Nov 1, 2024, 5:25 PM

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keen bison i have found the equations but idk what to do from there

what do you mean “found the equations”

keen bison Nov 1, 2024, 5:25 PM

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i have found 3 equations from that

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but idk how to like solve it from there

dusky apex Nov 1, 2024, 5:26 PM

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hmm

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you must have found a in terms of n, right?

keen bison Nov 1, 2024, 5:26 PM

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i like expanded it

dusky apex Nov 1, 2024, 5:26 PM

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actually, provide the equations

keen bison Nov 1, 2024, 5:26 PM

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wait ill send my equations

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rn_image_picker_lib_temp_97603bf2-4b30-4e02-9df1-1638088e92a0.jpg

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I just took a photo sorry it's sideways

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I matched the coefficients

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To get them

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The first 6 lines are the the only relevant bits tho

dusky apex Nov 1, 2024, 5:29 PM

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hmm

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,rotate

junior krakenBOT Nov 1, 2024, 5:29 PM

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dusky apex Nov 1, 2024, 5:32 PM

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junior kraken

was it

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divide the first line by the second

keen bison Nov 1, 2024, 5:33 PM

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wdym

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i tried dividing 8 = a^n and then doing that again but idk it didnt get me anywhere

dusky apex Nov 1, 2024, 5:34 PM

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they’re is a way to find n

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subsitution

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but it is horrendous

keen bison Nov 1, 2024, 5:35 PM

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like sub in a^n for 8 in every situation

dusky apex Nov 1, 2024, 5:35 PM

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yes

keen bison Nov 1, 2024, 5:35 PM

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does that still not leave 8/a or 8/(a^2)

dusky apex Nov 1, 2024, 5:35 PM

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but that is bad

keen bison Nov 1, 2024, 5:36 PM

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in the other equations

dusky apex Nov 1, 2024, 5:36 PM

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rational is fine

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hmm i will screenshot this

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i don’t have paper rn

keen bison Nov 1, 2024, 5:37 PM

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oh n = log (8=a) then

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which makes it kinda better

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ugh this is such a gross question 😭

dusky apex Nov 1, 2024, 5:37 PM

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?

keen bison Nov 1, 2024, 5:38 PM

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Like for the NCR term

dusky apex Nov 1, 2024, 5:38 PM

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log(8=a)???

keen bison Nov 1, 2024, 5:38 PM

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Log 8-a

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I mean

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Mb

dusky apex Nov 1, 2024, 5:38 PM

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okay

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how is n=log(8-a)

keen bison Nov 1, 2024, 5:38 PM

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So

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log 8 = log (a^n)

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log 8 = n log a

dusky apex Nov 1, 2024, 5:39 PM

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oh yes

keen bison Nov 1, 2024, 5:39 PM

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...

dusky apex Nov 1, 2024, 5:39 PM

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yes

keen bison Nov 1, 2024, 5:39 PM

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so that gets rid of n

dusky apex Nov 1, 2024, 5:39 PM

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log8/loga

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doesn’t simplify to log(8-a)

keen bison Nov 1, 2024, 5:40 PM

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does it not

dusky apex Nov 1, 2024, 5:40 PM

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nope

keen bison Nov 1, 2024, 5:40 PM

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oh facts

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i got mixed up

dusky apex Nov 1, 2024, 5:40 PM

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lol

chilly gulchBOT Nov 7, 2024, 5:00 PM

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@keen bison

<:HelpIcon:1304095958283321385>| Help Reminder

Hello heyhey_704, this is a friendly reminder that your thread has been inactive for more than 24 hours. If you no longer need assistance, please consider closing the thread using the +close command.

keen bison Nov 7, 2024, 5:18 PM

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+close

forest bloom Nov 7, 2024, 5:50 PM

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+close

#binomial expansion + 3 unknown simultaneous equation