#Maths trial and error?
459 messages · Page 1 of 1 (latest)
Ummm
It seems like trial and error
But I think there might be a better way
Idk sry
The order of the digits doesn't change, which restricts our options considerably.
This is basically saying that we have 47.5 * 10^a + 38.627 * 10^b + 125.4 * 10^c + 1583.3 * 10^d = 4508.57 * 10^e, with a, b, c, d, e in Z, that is, integers.
Of note is that the final solution has six significant digits, whereas the most any of the summands has is five.
We should look first to the extreme digits of the solution, 4 and 7.
How many ways are there to sum the extreme digits of the summands to yield those digits?
Also, one of a, b, c, d, e is 1.
What do you mean by x10^e? Did you mean Eulers number
wait what?
u mean the total combo that we can make with switching the decimal places?
...I mean some integer e.
I said as much.
I do not.
oh
wait idk what u mean by that?
You're not OP.
i was just trying to solve it 😅
Okay. The only way to get a 7 in the last digit is for the sum of all the digits in the last place to be 7, right? So how many ways are there of doing that?
Is that before moving the decimal places or after?
After. Or more accurately, it doesn't matter. That's why I'm not talking about the nth decimal place, I'm just talking about the order of the digits.
Ohhh okay ty
i would suggest considering how you would create the starting digits of 45
No. Also, you're not OP.
😭
we r working together bro 😭
@fallow jolt tell him bro 😭
@left geode how do u approach this q then?
@left geode we are working together
@left geode could you pls help me and lmk how to approach the question
Did you follow what I was saying before?
how is checking last digits gonna work?
do we not need to check for other digits too?
It's a first step.
Yes but I don’t rly understand how to do it since u have to add all of them how is it possible to get more than one
Solution
Since u can only add all of them together once
The last digit won’t change
It will stay the same
It will.
It will change.
Depending on where you place the decimals.
Because the last digit is the sum of the last digits of the things you're adding.
That is, the digits that are in the same place as the last digit of the answer.
If you move the decimal place, a different digit is in that place.
What's 2 + 3?
5
What's 2 + 0.3?
2.3
See the difference?
Once I’ve found the specific arrangement of numbers that add together to give 7 as last how will it help later
it's still kinda trial and error tho right?
,rotate
...it's a bot command to rotate a picture so I don't have to tilt my head.
Mb 😭
Anyway, now we have to recall the original question; there's exactly one decimal place in the original presentation that's in the correct place.
Yes and each of those 4 have one that is in the correct place (the number that is underlined)
Do I have to keep switching them now until I find more
It also says "find all possible ways to alter the four incorrect decimal places", so I think you're supposed to do five cases, each one leaving one decimal place in, er, place.
Wait, (3) has 2 unchanged.
Oh yeah
I'm comparing them.
Okay
That one would be wrong, yes.
👍🏿
So all I do is shift the decimals one by one and add them all until I get 4508.57
Not quite.
Look, this is easier if you just use scientific notation.
Actually, this is way easier in scientific notation.
4.75 * 10^a + 3.8627 * 10^b + 1.254 * 10^c + 1.5833 * 10^d = 4.50857 * 10^e```.
Literally all you have to do is take the largest term on the left that's less than what's on the right, assume the powers of 10 match, subtract, and repeat.
Here we get b = e, a = e - 1, d = e - 1, and c = e - 2.
Or, in terms of a, b = a + 1, c = a - 1, d = a, e = a + 1.
And when the term on the left gets less than 1 * 10^e, you just subtract from the power of 10.
wait wait i don't understand this step
@left geode
Is 4.75 < 4.50857?
no
Is 3.8627 < 4.50857?
yes
😭
...why would you even try to answer a question you haven't read?
nooooo
...do you get it or do I need to keep going?
no 😭
Okay.
Ignore the multiples of 10.
Ignoring those, what's the greatest term on the left that's less than the term on the right?
What do you even mean by that?
like 3.8627 or 38627
...which one is in the equation?
This equation?
...if you like.
Wait.
You haven't clearly enough communicated what you're actually doing.
we were thinking of trial and error...
but i think there might be an efficient way
so we asked help
@left geode
You're not good at this "clear communication" thing.
What exactly does this mean?
4.75 *10^a + 3.8627 * 10^b ...
Use. More. Words.
yk how 4.75 > 3.8627?
i thought u said we need to put the largest number in the left to the smallest in the right
but nvm
idk how that's useful
...do you know how subtraction works?
yes
What's the biggest thing on the left that you can subtract from the right and still have the answer be positive?
The right of the equation.
ohhhhh
This is literally all about the EQUATION.
What. Is. The. Equation?
4.75 * 10^a + 3.8627 * 10^b + 1.254 * 10^c + 1.5833 * 10^d = 4.50857 * 10^e```.
Stop guessing.
What are the terms on the left of the equation?
4.75 + 3.8627 + 1.254 + 1.5833
No.
all times it by 10 ^ a or b or c...
?
💀
😭
what r u even saying
u asked me for what's in the left side of the equaltion
like the terms?
or did u mean the exponent?
like a, b, c or d?
@left geode
I said I can't right now.
whyyyyy
I said why.
Have u alr solved it?
@left geode
Stop bothering me, I cannot help you right now.
Have you heard of patience?
ye but i don't think i have it rn
😭
im stuck at this q for more than 3 days
and i NEED to solve it today
Have your friend who actually pays attention read over everything I've said so far and explain it to you. If they need help, I'll help them.
Okay
Okay so yk how he said on the left and subtract from right but keep positive
That would be
ye...
4.75-1.5833
Mb he said farthest left and right
😭
Then after that he WAS gonna explain until u annoyed him 🤦
Yes because I’m not the help I’m the one who asked the q
no i was gonna ask it but u said u were gonna ask it
^
4.75 * 10^a + 3.8627 * 10^b + 1.254 * 10^c + 1.5833 * 10^d = 4.50857 * 10^e
An equation has a left side and a right side.
Okay so 4.75-4.50857
Ohh
Yes.
Ohhhhhh
how is that gonna help to solve this q tho?
How is it not?
What's the biggest thing on the left?
on the left?
ummmm
4.75 * 10^a
it also depends on the valued of the a tho
@left geode
Stop. Pinging. Me.
Ignore that part.
oh mb 😭
oh then it's 4.75
If you subtract that from the right, will the answer be positive?
no
So what's the next biggest thing on the left?
If you subtract that from the right, will it be positive?
yes
That means b = e. Do it. What do you get?
wait wait how?
...you're asking me how to subtract?
ummmm wait lemme read thru it
Do that before you bug me with questions.
but what if e = 2 and b = 1? u still gonna get postive right?
Then our equation is false.
Don't overthink it, this is just a more efficient version of the "how do you get the first digit" thing.
?
Go get your friend.
I'll explain it to them, but you don't listen well enough.
Hey. So read back and see if you get it from what I've said.
Okay
Oh wait so r u saying that the x10^b is also equal to the x10^e since the right when it’s subtracted from the left that’s the highest possible number to get a positive?
...I guess I might be saying that.
Oh okay
Or at least what you meant by that.
Yeh
Am I on the right track
Then do u assume numbers for a, c, and d and then do u find the right combination for a, c, and d to reach 0.64587
@left geode
Oops sry mb
Just saw the stop pinging now
Why assume e = 0?
You can, but your friend is way too much for me right now.
Oh okay
I didn’t know how else to approach it
The right side is still multiplied by 10^e, and now you need to multiply/divide by 10 to get it to 6.whatever * 10^(e - 1). Keep it in proper scientific notation.
...no.
I'm talking about doing the process you did before.
Oh okay
Low blood sugar, like I said.
👍
please eat something
yeah, do what micabo said.
like fed up with me
I have. Not enough, yet, but I did eat something.
why would they joke about low blood sugar
nobody
I was trying to, but the other person in here was annoyingly insistent.
@small bison
An escalator goes round and round, the number of steps remain constant.
The only clue is 60 steps and 42 steps, which is 51+/-9, so 102 steps altogether with 51 above and 51 below.
This is what he got^^^
@small bison
Start a new thread.
Oh Kk
I finally get what u were saying
Check the other thread
.
can u help us finish the question
We have found 4 solutions
@misty grotto
These r the 5 solutions we found r they right
@misty grotto
i think there's only 3 solution
noooooooooooooooooooooooooooooooooooooooooooooooooooooo plsssssssssss
noooooooooooooooo
im sry
it's just that we r in an urge
we NEED to finish this q today
😭
it would be helpful if the information concerning the question wasn’t split across seven different threads
it would also be helpful if you were slightly competent, but i suppose you can’t help that
were you going to provide me with the question from which it came?
or do you want me to guess from your working out
oh it’s still the same one
i told you there were 3 already
and why are you in this thread
idek 😭
only three right?
i left because i thought you already had the answer but then it turns out you drastically mess up whenever left unsupervised for two minutes
😭
i think i have the answer but just need u to confirm it
you do not; there are three answers and you have 4 or 5
^^^
i'll send them now
oh the first one and the 5th one are not the solutions
right?
yes
Could u pls explain the positioning method again but rly simply
dang micabo
i mean understandable but dang
it took me more than an hour last time and i’ll be damned if i willingly do it again
read through #1300533980122189965 or ask your friend (and check that they understood the explanation)
Their friend is worse than they are.
three pings from the same person for the same reason trying to summon me like some low-tier math demon while i was sleeping, then at least two more between the two of them when i woke up and decided that i had better things to do than interact with people on discord
their friend at least has the correct answer
My friend is offline and I’m pretty sure he just got the answer by shifting it i wanna know like the method just summarised
So we aligned the numbers then shifted the decimal to get the final number
And like how did u know where to put the numbers in how did u arrange them
good job
Ik it was to get a correct answer at the end so it would all equal to the final number but then isn’t that just trial and error if u have to keep moving them around to find out which is correct
@helpers pls help us
someone pls help
it's urgent 😭
im now not even allowed to ping anyone 😭
pls help
im dying here
it's 3 in the morning
plsssssssssssssss help
im beggin
Go to sleep.
no i rly can't bcuz im soooo close to finish this q
just summarise how u arranged those num to get 450857
that's all i need
it doesn't even have to be a long explanation
plssssss
Go. To. Bed.
I literally explained from beginning to end the process.
If you don't know it, it means you weren't listening.
Fortunately, this is a text medium with a log of interactions.
So go back and read it again.
Or just go to bed.
That's the better option.
But then, if you were smart enough to take the better option, you'd also be smart enough to listen the first time you're told something.
i did can u pls summarise how u arranged those num in the right way to get 450857
😭
it does'nt have to be long
pls 
The trick to arranging them the right way is to not arrange them in the wrong way. Now go to bed.
💀
Another trick is to know the right way, and then do it.
is it just trial and error then?
No.
I did. Yesterday. You didn't listen.
i didn't understand 😭
Because you didn't listen.
pls atleast two lines
If you didn't listen the first time, why should I tell you a second time?
Still, what's going to be different a second time?
maybe i can get it this time
but summarise in a diff way than u did b4
so i'll get it this time
No.
bro u spent a lot of time refusing to summarise
u coul'dve used that time to summarise
😭
Take "no" for an answer.
Take "no" for an answer.
if u r a helper why not help bro
I did. You didn't listen.
ok ur no help to me bro
You do understand that I'm a volunteer, right? I'm here doing this for free. I'm not your math slave.
i didn't understand the way u taught yesterday
kk but im asking other helpers too
And they're all getting tired of you.
Because you treat them all like your math slaves.
i don't bro 😭
all i did was ask q when i don't understand
this whole conversation couldve been over like 10 mins ago 💀
You pinged us incessantly. You don't respect our time. You think we have nothing better to do than sit in a channel at your beck and call and walk you through the same problem fifty times in a row all day.
alr then if u can't explain it to me it's fine
i'll close the thread
😥
😭
+close
You are not authorised to close this help request!
I got upto this bit
But then ur blood sugar went low (hope ur feeling better now) and we both got stuck sorry for the unnecessary pinging and explanations u had to give tysm for how far you have helped us
#1300533980122189965 i actually had a whole logical method in here that i explained, there was barely any trial and error involved
i had already linked it to you
i’m actually done with you
please refrain from saying things like this again.
@fallow jolt
Hello .yo..., this is a friendly reminder that your thread has been inactive for more than 24 hours. If you no longer need assistance, please consider closing the thread using the +close command.
