#Im supposed to calculate the distance traveled by a pendulum and I need the formula
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are you looking for the arc length of the path the end of the pendulum takes?
Im looking for the arc length after 3 seconds
length or displacement?
the displacement is 10cm
right, to start with
if we're solving for final displacement the answer is going to be different than if we solve for the total distance the pendulum travels
the final displacement is only relative to its start and end position
that makes sense yea
the formula i found so far is A sin(2pit/T)
but when I put it in python the number that comes out is not the exact same as what its supposed to be as annotated
hold on ill screenshot what I have
this is solving for angular velocity, not displacement
actually not even that
use cos in that function
when I do that makes it even worse
what is the lower case t in your formula?
angular displacement = Acos(ωt), where ω = 2pi/T
1 second is lower case t
is 3 seconds your period, or is that the total time the pendulum is swinging for
no i mean why do you have it.
oh just cause it was in the formula I saw, I know it doesnt make a difference
the answer that is supposed to come out is annotated as 0.06599551597515042
the one I get with my formula is 0.06249700733728915
and the one I get with Cos is 0.07806487093362051
are you inputting degrees instead of radians?
yes, but it is starting with a 10cm displacement (i imagine from statinc equilibrium, unless you have a wall that the pendulum is sitting relative to)
i dont
free body diagram
the circle diagram right
no i know
lemme make one and demonstrate what i mean
actually you dont need to worry about forces here
ignore the right thing
so im assuming you need to find the displacement m travels after 3 seconds?
yea
So your formula should look like A * cos(ωt + θ)
but how do I calculate theta
basic trig, its arctan(50/10)
arctan length / displacement?
no excuse me its arctan(10/50)
other way around
not quite
so tanθ = opp/adj
we know the lengths of both the opposite and adjacent sides which is why i picked tangent
then use the inverse operator to solve for theta
so roughly 0.197
now you need to solve for omega, which is 2pi/T
t is the period, the time it takes the pendulum to complete one swing back and forth
you'll need to use some angular kinematics equations to find that
i already got omega and the period
oh perfect then youre done
yes
how did you calculate omega
which i did with 1/(2pi square root of (L/g))
multiply your current value of omega times 2pi
it comes out even more wrong
lemme take a picture of my code i hope its understandable
sweet python
could it possibly be that i have the right answer and my prof is wrong
omega is the frequency here or period
yea my brain is melting
sorry mate
id do some youtubing on simple harmonic motion before attempting this, should clear things up
im still not 100% sure what your prof is asking tbh
ill do that then, i spent 6 hours today already on this one problem 
thanks for your help man
yea honestly prof just might be wrong
@upper crescent
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