#hi what is this question asking
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omg i cant why is this so hard
Tide is just the rising and falling of the water. The variation in height should be the period, you are correct.
which one is 1B?
oh, right
“height variation” is just a way to describe the function tracking the tide height (2sin(15x)+3)
I was just trying to recall the formula for period. Is it 2π\B ?
So I think everything checks out!
It was just weird wording since the model represents height of tide, yet the answer is asking for the period. So I could see that being confusing
oh okay thank youu
what abt c?
is it just
idek atp
how do u find max and min again
is it b x the period
wait no its d plus minus A right
but theres no d
so its just -2 and positive 2?
@polar trench
It looks like you have a +3
that shouldn’t affect the time taken to travel from minimum to maximum
you may note that the period describes the time between two minimum points, and a maximum always occurs in the middle of two minimums
alternatively, you may also choose to find their values (as twitch said, add 3) and then find the times where these values are attained
@mental knoll is correct, the heights will be between -2+3=1 to 2+3=5, but they are asking about the distance along the horizontal axis
So the easiest strategy is to divide your period in half as suggested
is it 6 for maximum and then -6 for minimum??
oh wait what
so the place between my maximum and minimum is the the period in half?
If the period is 2π/15 this gives you the horizontal distance from maximum to maximum, so yeah you got it! Half that is what we want
Again it's a bit weird since the number of hours is pi/15 and not a whole number
so would it be 2pi/30
this is so confusingg
simplify that
pi/15?
The max and min should be at 1 and 5 I believe
wait so
im trying to find the mean line aka between the max and min line
?
and that is half the period?
I was just trying to show that the mins all happen at 1 and the maxes all at 5 with the picture
yes
Yes π\15 is the distance from one max to one min
ahhh
I think your calculator must be in degrees since you get 90 and -90
oh should i be getting radians?
Yes that would help a bit
What you were doing is correct if you want to find an x value where you get a max or min, but we need radians instead of degrees
i got 1.5708
Awesome!
is that correct!!?
Yep that's what I got for sin inverse of 1. Now divide by 15 to get the x value of interest
that is π/2, yes
i suppose i could
I was just trying to connect my graph to the maxes and mins. I think you'll need that solving strategy we just used for the last part.
But I'm sweepy
for 2d?
yes
i think you should have more times than that
wdym
2d asks for the time(s) when the tide height is 4 meters
how do i solve it?
are you sure this is in radians and not degrees?
yes
i think the questions would make more sense if they were degrees
wait so do i switch it?
wait
okay
so
i switched to degrees
and go 30
then divided by 15
and got 2
wait is this question refering to unit circle
would it be possible at all to ask a teacher for clarification?
oh
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