#Finding COmplex Roots
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to find complex roots generally youre meant to just factor into an irreducible quadratic
like ax^2+bx+c but the discriminant is less than 0
however, this one is not factorable in fact this is your answer which is not hand computable
so are you meant to use a graphing calculator or something?
Idk what that is
@lime mantle Help me solve one of these
Maybe we'll do uhh
lemme think
number 13
okay if this is no calculator i assume it is factorable
so whatever you put there idk where you got that
The one you were talking about isn't on there.
i know
anyways, do you know the rational/integral root thereom
Did you just make it up?
yeah
yeah
Well, don't do that. That's why it wasn't working.
Actually no i didnt
its from a textbook
I lied
ok but
Even with my calculator it wont give me complex roots
go with factoring first
And what does the textbook say to do with it?
wait what are you putting into your calculator
Im putting the unfactored form of this which owuld be
x^3 - 2x^2 - 3x + 6
And I have a ti-84 plus ce graphing calcukaltor
okay so again
^^
basically what your cubics with complex roots will look something like
(x^2+5)(x-3) or something
or more complcated, (2x^2+3x+6)(x+4)
but notice how we cannot factor down that quadratic
it has no real solutions
meaning it must have complex ones
also, all polynomials with a degree of n must have n roots
if there are m real roots, then n-m of them are complex
have you done complex roots of quadratics
I dont think so
tldr just use quadratic formula
+- sqrt-1
if there is a remainder
im learning it myself lol
oh
If I factor (x-2) out of (x^2 + 2x + 3 + 4/x-2
thats dividing the polynomial
mhm
however
when you factor you want to make the thing simpler
the 4/(x-2) makes it more complicated
so when youre trying to factor things above degree 3
Ok so
do you know the remainder theorem
this equation has complex roots
and i check my work everythings correct
But idk how to fin dthe complex roots
the problem is
you dont know how to factor a cubic
at least from what i see
lets do that first
and then the complex part comes after
like x^3 - 2x^2 + 5x +6/x+6
ik what to divide
okay, so factor q13 then
actually
or they cant be factored conventially
they can if the question makers choose specific numbers
a vast majority of them cannot be factored
however, if the question says no calculator you basically assume specific numbers are chosen such that it is factorable
anyways
hows factoring 13 going
Not so well
what do you have so far
(x^4 - x^2)(-4)(x^3 -3x+3)
and what work did you do to get that
what
uhh what
you cant just vanish the x^4 lol
what did you do exactly
alr gn
i said this, and it was because you were continually using the grouping method when you could just use RRT
just learn how to identify and use rational root theorem before you even start factoring quartics
i believe your problem is that someone teaches/tells a method, you jump right into it and only stick with that method
you need a toolbelt, not a singular tool
and master all of the tools in your toolbelt before you start using them
because then you could harm yourself and your learning
so, learn to identify when to use certain tactics first before solving
an no, i’m not being a “jerk”, i’m telling you the truth.
you need to learn the concept for anything new you start learning before you start using it
just please heed my advice
if you don’t i can guarantee you’re going to be just as confused with anything you learn as you are now
I think even that's a mistake. Viewing math as a series of discrete tools to be applied to seemingly arbitrary circumstances is itself damaging to learning. It's best to learn to see math as a unified system of logic and learn the proofs of why using a certain technique yields a particular result.
||agreed but the point of this is to explain not to bash one thing over and over without understanding its applications||
||That's what learning the proof is for.||
@weak spire
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