#straight lines
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i have considered the points as a and b
on the axes
ok
have you found point P
a,b
so you will need a line through P perpendicular to AB
yea
so slope of that line is -b/a
eq is like y/x-a= -b/a
so ay= -bx+ab
bx+ay-ab=0
length of perpendicular is c/2 too
c is?
the length of the diagonal..
why is the length of the perpendicular c/2
diagonals in rectangle are equal
and they bisect eachother..right
but they are not perpendicular
OH
OH NO
shucks
mb
ok wait now ill try
ok nvm im not getting anywhere
try finding the equation of the line through P perpendicular to AB
you can determine its gradient
i did
yb-ax=b^2-a^2
ok
now intersect that with line AB
yea
x+y= b+a - ab/b-a
is what i got
or wait
i got x = - b^2+ a^2/a^3
sorry i mean a^3/(a^2-b^2)
yb-ax = b^2-a^2
bx+ay = ab
were there brackets for this?
i don’t quite think that’s correct
yea
but i could be wrong
i wrote eqns wrog
;-;
what was your y value?
one se
c
use these equations
b^3/(b^2+a^2)
x = a^3/(a^2 + b^2)
y = b^3/(a^2 + b^2)
would this seem accurate?
ok wow
ig i got it..
as a^2+b^2 = c^2
i dont get it
💀
after i get this wht do i do? a^3/c^2 + b^3/c^2
now calculate x^(2/3) + y^(2/3) and pray to a deity of your choice
why lol
why the calculation or why the praying?
2nd.
the calculation is because you need to prove x^(2/3) + y^(2/3) = c^(2/3)
theres nothing complicated.,
the prayer is optional
damn u smort
as heck
thanks
@marble oyster
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