#straight lines

72 messages · Page 1 of 1 (latest)

marble oyster
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well pls help me.. dont give me the ans try to help me think ig..

oak eagleBOT
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marble oyster
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have you drawn a diagram?

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yea

marble oyster
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on the axes

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ok

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have you found point P

marble oyster
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so you will need a line through P perpendicular to AB

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yea

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so slope of that line is -b/a

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eq is like y/x-a= -b/a
so ay= -bx+ab
bx+ay-ab=0

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length of perpendicular is c/2 too

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c is?

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the length of the diagonal..

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why is the length of the perpendicular c/2

marble oyster
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and they bisect eachother..right

marble oyster
marble oyster
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OH NO

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shucks

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mb

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ok wait now ill try

marble oyster
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try finding the equation of the line through P perpendicular to AB

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you can determine its gradient

marble oyster
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yb-ax=b^2-a^2

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ok

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now intersect that with line AB

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yea

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x+y= b+a - ab/b-a

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is what i got

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or wait

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i got x = - b^2+ a^2/a^3

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sorry i mean a^3/(a^2-b^2)

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yb-ax = b^2-a^2
bx+ay = ab

marble oyster
marble oyster
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i have added them now

marble oyster
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yea

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but i could be wrong

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i wrote eqns wrog

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;-;

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what was your y value?

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one se

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c

marble oyster
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b^3/(b^2+a^2)

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x = a^3/(a^2 + b^2)
y = b^3/(a^2 + b^2)
would this seem accurate?

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ok wow

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ig i got it..

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as a^2+b^2 = c^2

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i dont get it

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💀

marble oyster
marble oyster
marble oyster
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why the calculation or why the praying?

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2nd.

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the calculation is because you need to prove x^(2/3) + y^(2/3) = c^(2/3)

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theres nothing complicated.,

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the prayer is optional

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damn u smort

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as heck

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thanks

mint nacelleBOT
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@marble oyster

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robust ledge
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+close