#Solving polynomial functions algebraically
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any specific example?
It says on my book module 3, solving polynomial equations algebraically
Ill give u a question
the teacher gave us then
cuz this is from youtube
4x^3 + 12x^2 - 9x - 27 = 0
that question is solved, but I wrote down what he wrote, so ill type how this was presented to me
if you can get into a form like a(b+c) + d(b+c) = 0, it can be grouped into pairs --> (b+c)(a+d) = 0
cuz i didnt understand it
js fixed one thing
its, cubed not squared
mb fr
the teacher paired it
and he wrote
as he should
(4x^3+12x^2) + (-9x-27) = 0
you made a typo
okay
from what i recall he said pick the lower exponent/power from the two
which was
^2
and he he simplified the whole equation even smaller
and smaller, it was confusing to me tbh
what?
let me show ya
my handwriting is insane LOL mb mb, I was writing fast
this i did NOT understand
he said pair it first, and he showed it
hm ok
then he said from between the 4 and 12, pick the lower power
which was ^2
and then i got thrown off
we are trying to factor each pair
when he showed me how to get the 4
I see
for example, start with (4x^3+12x^2)
and pick out every common factor from it
mhm
the 4 comes from being a factor of 4 and 12 both
uhuh
Wait
How would I get the factors exactly?
Wait
He said 2 divided by 12 is 6 and 2 divided by 4 is 2 and he kept dividing
Until 12 became 3 and 4 became 1
And he stopped dividing them
Are those the factors ?
the 2 and 2 r factors, correct?
wait
so u
kept dividing the
4 into 1
and it became x? since x is 1
while 12 became 3 after dividing it those many times
how do you know when to stop dividing
1 and 3 don't have any common factors
yes
1 doesn't count because 1*anything = itself
I see, so 4, would be 4 2 and 1
I understand, im js tryna solidify it
that removes, hella confusion
teacher confused the hell out of me
in this case, it would be, 1, 2, 5, 10
if both of the numbers are divisible by 10, sure
I see, alright then
generally we will seek to take the greatest common factor out
for example, here, it is 10
(edited)
So we picked 4, because its the factor of both, and its the greatest common factor
alright ty
u can continue
now you have to take out the powers of x
how so?

consider the largest power of x dividing both x^3 and 3x^2
the factor is 4, its the greatest factor
and between the two powers
the lower is 2
and so u use that
which becomes 4^2
correct?
4x^2
right right
forgot the x
okay. and the number that cant be divided anymore
is 1 and 3
so its x and 3
making it 4x^2(x+3)
the greatest factor between the two is -9
the least 27 can get to is 3, and 9 is 1, right?
ignore da plus and minus, i mean js number wise
is that correct?
-9(x+3)?
Okay, what’s the next step?
factor out (x+3)
so we have (4x^2-9)(x+3)
so u js take the two numbers out of the equations and put em together, and u take the common pair which is x+3 and u put it aside
and das it
👍
I aced the exam
yw
nice
@molten hinge
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