#Solving polynomial functions algebraically

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molten hinge
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I need help with this, and it's explanation, I got an exam on wednesday frfr

eager talonBOT
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molten hinge
charred pivot
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any specific example?

molten hinge
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this I guess

charred pivot
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you can't really solve for that; it's not an equation

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did you mean factor?

molten hinge
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It says on my book module 3, solving polynomial equations algebraically

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Ill give u a question

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the teacher gave us then

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cuz this is from youtube

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4x^3 + 12x^2 - 9x - 27 = 0

charred pivot
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try to factor it

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this one can be grouped

molten hinge
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that question is solved, but I wrote down what he wrote, so ill type how this was presented to me

willow needle
molten hinge
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cuz i didnt understand it

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js fixed one thing

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its, cubed not squared

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mb fr

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the teacher paired it

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and he wrote

charred pivot
molten hinge
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(4x^3+12x^2) + (-9x-27) = 0

charred pivot
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you made a typo

molten hinge
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?

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that

charred pivot
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fixed

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yes

molten hinge
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okay

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from what i recall he said pick the lower exponent/power from the two

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which was

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^2

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and he he simplified the whole equation even smaller

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and smaller, it was confusing to me tbh

charred pivot
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what?

molten hinge
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let me show ya

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my handwriting is insane LOL mb mb, I was writing fast

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this i did NOT understand

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he said pair it first, and he showed it

charred pivot
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hm ok

molten hinge
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then he said from between the 4 and 12, pick the lower power

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which was ^2

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and then i got thrown off

charred pivot
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we are trying to factor each pair

molten hinge
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when he showed me how to get the 4

molten hinge
charred pivot
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and pick out every common factor from it

molten hinge
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mhm

charred pivot
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the 4 comes from being a factor of 4 and 12 both

molten hinge
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uhuh

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Wait

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How would I get the factors exactly?

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Wait

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He said 2 divided by 12 is 6 and 2 divided by 4 is 2 and he kept dividing

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Until 12 became 3 and 4 became 1

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And he stopped dividing them

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Are those the factors ?

charred pivot
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2 and 2, yes

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(2*2=4)

molten hinge
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the 2 and 2 r factors, correct?

charred pivot
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yes, so you can take them out

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4(x^3 + 3x^2)

molten hinge
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wait

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so u

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kept dividing the

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4 into 1

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and it became x? since x is 1

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while 12 became 3 after dividing it those many times

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how do you know when to stop dividing

charred pivot
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1 and 3 don't have any common factors

molten hinge
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for a factor there has to be no remainder when dividing correct

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?

charred pivot
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yes

charred pivot
molten hinge
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I see, so 4, would be 4 2 and 1

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I understand, im js tryna solidify it

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that removes, hella confusion

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teacher confused the hell out of me

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in this case, it would be, 1, 2, 5, 10

charred pivot
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if both of the numbers are divisible by 10, sure

molten hinge
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I see, alright then

charred pivot
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for example, here, it is 10

charred pivot
molten hinge
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So we picked 4, because its the factor of both, and its the greatest common factor

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alright ty

molten hinge
charred pivot
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now you have to take out the powers of x

molten hinge
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how so?

molten hinge
charred pivot
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consider the largest power of x dividing both x^3 and 3x^2

molten hinge
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the factor is 4, its the greatest factor

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and between the two powers

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the lower is 2

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and so u use that

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which becomes 4^2

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correct?

charred pivot
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4x^2

molten hinge
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right right

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forgot the x

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okay. and the number that cant be divided anymore

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is 1 and 3

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so its x and 3

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making it 4x^2(x+3)

charred pivot
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4x^2(x+3)

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now do the same with the other one

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(-9x-27)

molten hinge
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the greatest factor between the two is -9

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the least 27 can get to is 3, and 9 is 1, right?

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ignore da plus and minus, i mean js number wise

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is that correct?

charred pivot
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yes

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and it's common practice to take the - out

molten hinge
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-9(x+3)?

charred pivot
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yes

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so you have 4x^2(x+3) - 9(x+3)

molten hinge
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Okay, what’s the next step?

austere willow
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so we have (4x^2-9)(x+3)

molten hinge
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and das it

molten hinge
molten hinge
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tyall both

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Lol

austere willow
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yw

charred pivot
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nice

latent nymphBOT
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@molten hinge

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indigo crystal
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+close