#Limit: Why -1/4 and not 0?
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because when you “plug in” infinity, you get $\lim_{x\to\infty} 4x-x\cdot\sqrt{16}$
;( | 追放された興奮
(notice i am able to omit the absolute value because x is approaching positive infinity)
Yes but don't you still get 4x - 4x, where x approaches infinity, making the whole thing approach 0?
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@dim jay
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