#sigma
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The answer is 9, our teacher wants us to solve it and prove that the answer is 9
okay
we can start by rationalizing the denominator first
Shit
?
Fk fk I skipped highschool algebra
so do you know or do you not know?
Wait holdon the organic chemistry teacher has a tutorial for it
no lol
why am i doing this in the first place 💀
anyways
Okay start
let’s propose we have an irrational number $\sqrt{a}+\sqrt{b}$
;( | 追放された興奮
I have a pen and a paper
as in the equation
Mhm
to rationalize the denominator
Telescoping series!
we have to multiply by its conjugate, or $\sqrt{a}-\sqrt{b}$
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no shit 💀
Its opposite?
But yes, rationalize like how this dude is saying
So sqrt(i + 1) + sqrt(i) multiplied by sqrt(i+1) - sqrt(i)?
yes
butt
multiply on the numerator and denominator
so we can have a factor of one
By that you mean?

Sorry im a bit of a dumbass
by $\frac{\sqrt{i+1}-\sqrt{i}}{\sqrt{i+1}-\sqrt{i}}$
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right concept, but look ^
OHHHH
gotchu
an irrational multiplied by its conjugate is equal to a-b
so in this case
denom would be i+1-i
which is?
Do I just straight up multiply them?
There is two sqrt(i + 1)
Would that make it (sqrt(i+1))²
yep
same with sqrt(i)
in general though
$(\sqrt{a}+\sqrt{b}) (\sqrt{a}-\sqrt{b})=a-b$
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now we have $\sum_{i=1}^{99} (\sqrt{i+1}-\sqrt{i})$
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this is telescoping
Now what how do I use the properties of sigma notation on this
Yes but there are radicals
you don’t 
see how it is i+1 compared to i
let me write out a few terms of the sum to show you
Okay
sqrt(2)-sqrt(1)+sqrt(3)-sqrt(2)+sqrt(4)-sqrt(3)...sqrt(100)-sqrt(99)
see how the sqrt(2) and sqrt(3) cancel in this sum?
because there is a negative and positive part for it?
I have completely no idea why they cancel out
look at sum again
and look for coefficients of sqrt(2) and sqrt(3) terms
Do you mean the sqrt(2) and negative sqrt(2)
Or am I being dumb
yes, sure
sqrt(3) also has a negative component in the sum
Yeah
now u see how they cancel right
😔
Sorry but my mind cant process how sqrt(2) and sqrt(3) cancel out
ODJWPZJEKAKJF
Im hopeless
Lets just uhh skip that part
Im too much of a numskull
You can't proceed if you don't notice how the terms cancel out....
Look, there is sqrt(2) and -sqrt(2)
Add them.
that’s the whole concept of a telescoping series 💀
Yeah thats what I meant
Yh
Here
so what is sqrt(2)-sqrt(2)
Yeah
0
Yes, those 2 terms
what about sqrt(3)-swrt(3)
Same goes for sqrt(3) and ... so on
Fk I was just misunderstanding you
looooool
Yup
so this happens
for all of the numbers in the series
except for the first and last term
Mhm
i.e. -sqrt(1) and sqrt(100) in this case
OOOOOOO
Just observe those pairs...they all cancel out except for the first and last term, they dont have their respective negative factors.
I can see that
so $\sum_{i=1}^{99} (\sqrt{i+1}-\sqrt{i})=\sqrt{100}-\sqrt{1}$
;( | 追放された興奮
THANK YOU SO MUCH
So yeah, this is what you get.
That explains why the answer is 9
And that's just 10-1=9
Yup
Thank you for sticking with my numskull ass
i have had worse people 
Yeah same lol
You did a great job grapsing the concepts.
How do I develop my problem solving skills like y'all so I can be less of a burden
Practice?
And focus on improving your observation skills
spam practice
+close