#physics
170 messages · Page 1 of 1 (latest)
Hello
Alright
wait let me translate
$R=\mu N$
Where:
$R=\text{friction force}$
And:
$N=\text{Normal force}$
Leonhard Paul Euler
yess and mu is what we want to find
is it?
okok
Who uses R
yes
I'm just reasoning, I haven't solved this type of question in eonsn
but which pulling force? ðŸ˜
So the pulling force is 0.500kg×9.81m/s²
How?
but why not 0.200*9.81?
Because the 0.2kg object is not pulling
It is the one being pulled
i see
ok so the pulling force = 4.9
yess it does actually
And the normal force?
0.200*9.81
yes
,w 0.5×9.81 and 0.2×9.81
Yeah
does M also have a normal force?
Let me see what's M
the big object
ok
Since it's not resting on the table
Yes so
I'm joking
bahahaha
i mean u explained really good though
Yeah thanks
thanks for you time
I'm just rusty
i really appreciate it
So this was a good refresher on the old helping days
buut
You have more questions? 
Yeah
ok so
aw i am glad u did
ahahaha
Alright next question
if the speed is constant, should the sum of all forces equal to 0?
that why we have to use letters
to show all the forces we have used to calculate what mu is
but at least i understood how we got the value of mu
but i am not really sure how to show it by letters
ok
of course
The weight of the 0.2kg object, the normal force
and all forces for M is zero
yes
i have noo idea
i was trying but it seems wrong
@last cape
Hmmm
did u find out
Sorry I forgot about this
oh no worries
One sec, middle of something
noo its finee
?
My pleasure
I am sure you can do the letters part, supposedly its the easy one
hii
I GOT IT
Congratulations, sorry I forgot about it
thanks, no worries
@tiny crystal has given 1 rep to @last cape
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