#Geometry
bold salmon
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vivid patrol
wha completion is this?
bold salmon
wha completion is this?
must be some olympiad or somethin not sure
im preparing for an exam and a friend sent me this question
I'll ask him rq
It's called HMMT @vivid patrol
vivid patrol
It's called HMMT <@1245133657690214403>
Yes, I have heard of it
I am prepping for it
bold salmon
oh you are?
vivid patrol
Yes
bold salmon
that's interesting so have u done this question before?
bold salmon
wait what is HMMT? some entrance exam?
bold salmon
woah wait what
vivid patrol
yes
i think @runic depot would be more suited to solve this problem
i’m a bit rusty with this competition
bold salmon
alright
i didnt think it would be hard apparently it came in a 10th grade olympiad a year ago
vivid patrol
i didnt think it would be hard apparently it came in a 10th grade olympiad a yea...
no, HMMT is very hard
I would argue it is harder than the AMC 10A/B
runic depot
i think <@456226577798135808> would be more suited to solve this problem
what
this is a yucky problem
split into nicer shapes
then calculate side lengths for them all
length is easy because it is hypotenuse of triangle
width is not bad because it is the height of the same triangle
if you don’t calculate that the four rectangles have the same area, you did something wrong
runic depot
if you don’t calculate that the four rectangles have the same area, you did some...
(ok there is actually no need to calculate any side lengths; please do not do so, just note that width*height of the triangle in blue gives you the area of R1 and R2 simultaneously so this is true)
runic depot
this is a yucky problem
i take this back