#please help! I'm dead confused
75 messages · Page 1 of 1 (latest)
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for 7b):
- the smaller number always goes on the left
- the graph extends higher than y=0
for g), it does not occur at x=5; also, give coordinates
h) and i) are wrong for the same reason and you'll need to find the local minimum first to correct those
i'm not sure what you did for k and l
ive been stuck on this one
wdym by extends higher
so is it (-5, inf) for the range?
there are sections of the graph above the line y=0
yes
local minimum is (0, -5), right?
because thats the lowest curve or dip
yes
i just looked at which x line they were in tbh
so if you see the parts on the left and right, at the end they cross the x ine for -10
which i assumed would be the case
is i (-infinity, -5)? and h (-5, to infinity)
so 0?
so (-infinity, 0) and (0, infinity)
am i correct here?
yes, for i and h
use the solutions you found for j
thats where they intersect
so are we involving a union?
like (-infinity, -4) U (9, infinity)?
for k, yes
so are we using brackets for l?
cool
we have everything else under it so we can go from [-4, 9] right for f(x) <= g(x)? @boreal obsidian
we're using brackets for all of them, no?
yes
wait
did you mean [] these
all the numbers we found for 6 and 7 (besides infinite) has brackets right
yess
oh
like my notation right now is (-5, infinity)
i call () [] {} brackets interchangeably
kk, but im solid with parentheses, yes?
[ for this since -5 exists
this one should be correct
k is good too?
ngl, i am sort of running out of time to get l, could you tell me just how to do it
i wont close the post or anything, i want to preface that im on a time crunch
it's just [-4, 9]
you've already stated this i believe
my god, have i not answered this already?
no
as i said, i was on a time crunch and you were not active
but its okay
thank you both
truly
i hope you guys have a good rest of your day, i actually appreciate this from the bottom of heart ❤️
thanks @boreal obsidian @zealous helm
okay
@fossil fog has given 1 rep to @zealous helm @plucky oar
+close
