HELP ASAP | Mathematics | Page 1

main iron Sep 28, 2024, 9:08 PM

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atomic mothBOT Sep 28, 2024, 9:08 PM

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main iron

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glacial orchid Sep 28, 2024, 9:09 PM

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main iron

do you remember log rules?

main iron Sep 28, 2024, 9:10 PM

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Yes kind of yes

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Kind of

glacial orchid Sep 28, 2024, 9:10 PM

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$a log(b)=log(b^a)$

sterile rapidsBOT Sep 28, 2024, 9:10 PM

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dontfwcrux

glacial orchid Sep 28, 2024, 9:10 PM

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things like this

main iron Sep 28, 2024, 9:10 PM

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Ya ya

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It turns to x squared

glacial orchid Sep 28, 2024, 9:10 PM

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??

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oh yeah

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sry

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$log(a)+log(b)=log(ab)$

sterile rapidsBOT Sep 28, 2024, 9:10 PM

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dontfwcrux

main iron Sep 28, 2024, 9:11 PM

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Ya

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I know it

glacial orchid Sep 28, 2024, 9:11 PM

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$log(a)-log(b)={log}\left(\frac{a}{b}\right)$

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use all of these

main iron Sep 28, 2024, 9:11 PM

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Ya

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Ya but

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How

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Is the question 😭

sterile rapidsBOT Sep 28, 2024, 9:11 PM

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dontfwcrux

glacial orchid Sep 28, 2024, 9:11 PM

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main iron Is the question 😭

?

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,rotate

sterile rapidsBOT Sep 28, 2024, 9:12 PM

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main iron Sep 28, 2024, 9:12 PM

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Like how do I solve

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The

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Question

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With these rules

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I know x becomes x^2

glacial orchid Sep 28, 2024, 9:12 PM

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uh

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$log(x^2)=log(6x)-4$

sterile rapidsBOT Sep 28, 2024, 9:12 PM

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dontfwcrux

glacial orchid Sep 28, 2024, 9:13 PM

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because 3*2x is 6x

main iron Sep 28, 2024, 9:13 PM

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Ya from this step I don't really have a clue

glacial orchid Sep 28, 2024, 9:13 PM

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alright

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ill give you a hint

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how would you convert 4 into log(something)

main iron Sep 28, 2024, 9:14 PM

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4 into log ??

glacial orchid Sep 28, 2024, 9:14 PM

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yes

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i.e. solve for a in $log(a)=4$

sterile rapidsBOT Sep 28, 2024, 9:14 PM

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dontfwcrux

main iron Sep 28, 2024, 9:14 PM

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a^4

glacial orchid Sep 28, 2024, 9:15 PM

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...

main iron Sep 28, 2024, 9:15 PM

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😟

glacial orchid Sep 28, 2024, 9:15 PM

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solve for a

main iron Sep 28, 2024, 9:15 PM

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3am

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Oh

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10^4

glacial orchid Sep 28, 2024, 9:15 PM

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yes

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lol

main iron Sep 28, 2024, 9:15 PM

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Lmao

glacial orchid Sep 28, 2024, 9:15 PM

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so 4=log(10^4)

glacial orchid Sep 28, 2024, 9:16 PM

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sterile rapids **dontfwcrux**

we can use the subtraction rule here

main iron Sep 28, 2024, 9:16 PM

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How

glacial orchid Sep 28, 2024, 9:16 PM

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log(6x)-log(10^4)=?

main iron Sep 28, 2024, 9:16 PM

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Log (6x/10^4)

glacial orchid Sep 28, 2024, 9:17 PM

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yes

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so log(x^2)=log(6x/10^4)

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thus x^2=6x/10^4

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now solve for x

main iron Sep 28, 2024, 9:17 PM

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Hm

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Idk 😭

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6x to the other side?

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3am

glacial orchid Sep 28, 2024, 9:19 PM

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no

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multiply both sides by 10^4

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we get (10^4)x^2=6x

main iron Sep 28, 2024, 9:20 PM

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OH

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After that we take x^2 to the other side

glacial orchid Sep 28, 2024, 9:20 PM

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main iron After that we take x^2 to the other side

no

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we divide by x

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well

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technically you are correct

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but x cannot be zero in this case

main iron Sep 28, 2024, 9:21 PM

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Yes

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So we divide it

glacial orchid Sep 28, 2024, 9:22 PM

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yeah

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(10^4)x=6

main iron Sep 28, 2024, 9:23 PM

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We take 10^4 to the other side

glacial orchid Sep 28, 2024, 9:23 PM

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yeah

main iron Sep 28, 2024, 9:23 PM

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6/10^4

glacial orchid Sep 28, 2024, 9:23 PM

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yes

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👍

main iron Sep 28, 2024, 9:23 PM

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Okayy thank you

glacial orchid Sep 28, 2024, 9:24 PM

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alrigth

main iron Sep 28, 2024, 9:24 PM

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1_thumbsup

glacial orchid Sep 28, 2024, 9:24 PM

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should i give an example problem

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to make sure you understand

main iron Sep 28, 2024, 9:24 PM

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Ya sure

glacial orchid Sep 28, 2024, 9:25 PM

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3log(x)=2log(7)+log(x/2)-5

main iron Sep 28, 2024, 9:26 PM

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Logx^3=log7^2+log(x/2)-5

glacial orchid Sep 28, 2024, 9:26 PM

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main iron Logx^3=log7^2+log(x/2)-5

im not gonna help you out

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gotta do this on your own

main iron Sep 28, 2024, 9:27 PM

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Okay okay when I'm wrong in smth please do tell me kevinhart

glacial orchid Sep 28, 2024, 9:28 PM

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okay

main iron Sep 28, 2024, 9:29 PM

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The -5 will turn into 10^-5

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No wait just 5

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Log x^3=log(49xx/2)-10^5

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Then logs are gone

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So

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X^3=49 x x/2 -10^5

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3am

glacial orchid Sep 28, 2024, 9:33 PM

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wait

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not 2 x

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only 1 x

main iron Sep 28, 2024, 9:33 PM

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That's multiply

glacial orchid Sep 28, 2024, 9:33 PM

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x^3=49x/(2(10^5))

main iron Sep 28, 2024, 9:33 PM

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HUH

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I'm confused

glacial orchid Sep 28, 2024, 9:38 PM

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uh

glacial orchid Sep 28, 2024, 9:39 PM

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main iron Log x^3=log(49xx/2)-10^5

incorporate 5 into the log

#HELP ASAP