#hints
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so what
$C=\sum_{k=0}^{32}\binom{32}{k}^2=\binom{64}{32}$
#EqualityForWolf
$\sum_{k=0}^{n}\binom{n}{k}^2=\binom{2n}{n}$
Formula h kya nc0ncn??
#EqualityForWolf
generating function se prove hojayega
coefficient of (x^n) in expansion of ((x+1)^n(1+x)^n)
#EqualityForWolf
coefficient of (x^n) in ((1+x)^n(1-x)^n=(1-x^2)^n)
#EqualityForWolf
n even
nah
i mean
haan
series ke liye
kar sakta hai
actually
1-x^2)^n = 1-x^2+x^4-x^6...
No?
if $n$ is odd the coefficient of $x^n$ is $0$ but if it is even then the coefficient of $x^n$ is $(-1)^{\frac{n}{2}}\binom{n}{n/2}$
#EqualityForWolf
Lekin bhai (1-x^2)^n me cofficent C^2 kaise hoga?
((1-x)^n (1+x)^n)
#EqualityForWolf
,
this is not readable
we will not check your calculations
although we can confirm if your ideas are correct
so tell us the idea instead