#25 and 26 pls#
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$\textbf{26.}$ one may rewrite the sum as $\sum_{i=0}^{\infty}\abs{\cos x}^i$ and since $0<x<\pi$ we know that $\abs{\cos x}<1$ thus the geometric series is convergent
#EqualityForWolf
i assume that this is what the problem statement means, by "inscribed in an angle alpha". please confirm.
aren’t there supposedly two values of x for question 26?
No
@vernal sandal are you able to solve it with this
only one of them lies in (0,pi)
the expression is $4^{\frac{1}{1-\abs{\cos x}}}$
#EqualityForWolf
shouldn't x and π-x end up having the same value after all the absolute value signs?
ah
yes you're right
which gives two solutions in (0,pi)