#Point out my error pls. (Conditional Trigonometric Identities)

46 messages · Page 1 of 1 (latest)

tulip notchBOT
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livid current
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Pls ping me when replying

vale forum
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what is the question here?

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are you meant to prove something?

livid current
livid current
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ok

vale forum
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such a weird question

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there must be a geometric proof

dense orchid
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A,B,C are angles of a triangle

vale forum
livid current
# vale forum such a weird question

@vale forum
@dense orchid
It is meant to be solved the same way as other Conditional Trigonometric Identities

But this one doesn't satisfy RHS and LHS when I substitute random values that sum to 180°

vale forum
livid current
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Here's another way

livid current
vale forum
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how does it not solve

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???

livid current
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??

vale forum
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i think you’re wrong

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it subisitutes correctly

marble sand
vale forum
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check the pair (90,45,45)

marble sand
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i’m not sure what the question is

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i just read your working on the paper

livid current
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2A+2B+2C=2π
2A+2B = 2π-2C
cos(2A+2B)=cos(2π-2c)=> ....

marble sand
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which equals cos(2C)

livid current
marble sand
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cos is an even function

vale forum
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star

livid current
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I forgot :(
Cos is +ve in 4th quad.

vale forum
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your solution is correct

livid current
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but my first step is incorrect :(

vale forum
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i’m plugging in values

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and they wrk

livid current
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Like 0,0,180 or something

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but not all

vale forum
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i tried (30,60,90)

livid current
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I'll resolve it using cos(2A+2B)=Cos2C

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Then I'll be back

livid current
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sin²(2A)+sin²(2B)+sin²(2C)=2[1-cos(2A)cos(2B)cos(2C)] ; [A+B+C=π rad]

Finally solved ✅