logarithm

[vestal plover]

hi, i need help with d - solve the equation.
thanks.

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[vale island]

Hint: multiply through by e^x (which is fine since e^x != 0)

[vestal plover]

multiply through?

[vale island]

multiply both sides by e^x

/ multiply everything by e^x

[vestal plover]

aa ok

[vale island]

same thing by distributive property

[vestal plover]

but 0 multiplied by e^x is 0

[vale island]

yes

[vestal plover]

so i have to multiply all terms with e^x?

2 as well?

[vale island]

I said that a minute ago, yes

[vestal plover]

okok

but how did you see that 😭

that we should multiply with e^x

[vale island]

experience

you're just solving $u-2-\frac{8}{u}=0$

[wind tiger]

Omegabet_

[vale island]

just got rid of the fractions

[vestal plover]

now i have: 2e^x -2 e^x -8 =0
can i do e^x = u

i mean can i use substitution here?

[vestal plover]

ohh

[vale island]

Yes

[vale island]

Obviously this is wrong since e^x * e^x isn't e^x

[vestal plover]

well its not

but is it e^2x

didnt i write that?

[vale island]

Your last line doesn't have that

[vestal plover]

wait so e^2x is not the same as 2e^x?

no it cant be the same

[vale island]

Obviously?

[vestal plover]

ja

ahaha

my bad

[vale island]

3^2=9, 2*3^1=6

[vestal plover]

yess

true

[vale island]

But anyway you're just solving a quadratic now

[vestal plover]

mhm

[vestal plover]

i think i got it

ln 4 is the answer

[vestal plover]

+close