Triangle volume

[storm coyote]

Help plz?

[shrewd condor]

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[storm coyote]

you’re going to need p and q

thats all i have..

[mellow belfry]

...you're going to need to find p and q.

[storm coyote]

yes, sorry for the confusion

Pythagoras and Trigonometry in Three Dimensions is the topic name

[storm coyote]

so can u find the answer?

[storm coyote]

yes

thanks

but i was hoping you would find it

so what do i do?

consider length p

can you think of any way to find it?

um

no

ok, that’s fair

it’s part of a right angled triangle

so they p and q are the same?

[mellow belfry]

What's sin(H)?

[storm coyote]

no

51.34

sorry internt drop

[storm coyote]

oh

[mellow belfry]

Okay, one, no it's not, and two, I don't mean as a number, I mean in the triangle.

[storm coyote]

that’s H, not sin(H)

h

OH

[wild forum]

$V=\frac{7qp}{2}$?

[storm coyote]

0.78

[unborn rampart]

M

[storm coyote]

yes, but shh

[storm coyote]

yes

so whats q and p?

but what is it in terms of the triangle’s side lengths?

remember what sin is defined as

(do you have SOHCAHTOA? if not, ignore this message)

opposuet over hypotenuse

[mellow belfry]

Which equals what?

[storm coyote]

so q/41

[mellow belfry]

...almost.

[storm coyote]

p?

is adjacent

[mellow belfry]

...what's the hypotenuse again?

[storm coyote]

?

[storm coyote]

no, it is q

square root of 41

you’ve just missed something in the hypotenuse

[storm coyote]

yep

[mellow belfry]

Which is not what you wrote. You just wrote 41.

[storm coyote]

sorry

[mellow belfry]

But yes, q/sqrt(41) = sin(H).

Which means q = sqrt(41) sin(H).

[storm coyote]

and sin is 0.78

so 0.78 times sqrt 41?

[storm coyote]

(i think they were just correcting their mistake)

so q is 4.99?

i think you could round it to 5 here

4.99444

[mellow belfry]

I get more nines than that.

[storm coyote]

i would suggest not being too quick to round your values

[mellow belfry]

Except sin(51.34 deg) doesn't equal 0.78, does it?

[storm coyote]

i guess we'll listen to yours

it does

sin(51.34 deg)

5 decimals i think i missed

my bad

so its4.99998

call it 5, i think

[mellow belfry]

It's probably best to use exact values until we arrive at the final answer, we don't know how many digits we're gonna need.

[storm coyote]

ok

[storm coyote]

nearest whole number

but that is also true

[mellow belfry]

Which is how many digits long?

[storm coyote]

i just don’t like decimals

[mellow belfry]

Who said decimals? I said exact values.

[storm coyote]

15

[mellow belfry]

15 is 1 digit long?

[storm coyote]

two

15 isn’t the answer?

is it

[storm coyote]

51.34 is a decimal

[mellow belfry]

No, it's a demonstration of my point that a whole number can have any number of digits.

[storm coyote]

unless you’ve planned to make that a fraction too

oh well

exact values it is

how do we want to find q?

soccahtoa?

ok

so same way as we found p

ohh

so q/sqrt 41

[mellow belfry]

We could also just use the Pythagorean theorem.

[storm coyote]

if we’re using exact values, that will be slower

both quared = hypt squared?

[storm coyote]

ok

[storm coyote]

(sum of), but yes

so q2 +4.99998 square = sqrt 41 square?

[mellow belfry]

And actually I way screwed it up when I did it that way, so point taken.

[storm coyote]

yes

you should get q being very close to 4

so 4 isq

is q

well…

i mean, no, but also yes

so q2 = sqrt 41 square + 4.9998 squrare?

it is sufficiently close to 4 to not actually affect the answer

[storm coyote]

you were right the first time

so its q2 = sqrt 41 square + 4.9998 squrare?

[storm coyote]

typo, sorry

[storm coyote]

no

turn the + into a -

so q2 = sqrt 41 square - 4.9998 squrare?

yes

oh yea

oh so...let me se

is it:

you added them again

oh yea

wait

is that right?

yep, now square root that

so 4?

close enough?

yea a lot ur right

here, the error is too small to affect the answer

now that we have p and q, can you find the volume of the prism?

i guess

no i cant

google is not helpful

HOW TO DO THIS?

@storm coyote and @mellow belfry thanks

[keen spindle]

@near rivet has given 1 rep to @vague schooner @mellow belfry

[storm coyote]

😍

[mellow belfry]

The volume of any prism is equal to the area of the face times the perpendicular length.

[storm coyote]

what on earth

ignore that

[storm coyote]

ok, let’s find the area of the base triangle first

[nimble pilot]

dont fucking do that

just do base*height like any other 2d shape

except for this one base is 2d and height makes it 3d

[storm coyote]

can u do it, my brain not brainning?

[nimble pilot]

uh okay...

[storm coyote]

thanks

[nimble pilot]

for this?

[storm coyote]

ok

[storm coyote]

yea

[nimble pilot]

i cant give answers to the original question

[storm coyote]

you have a base and a height

[nimble pilot]

its against the rules

but i can help

[storm coyote]

can you find the area?

[storm coyote]

of?

the triangle?

[nimble pilot]

so $\mathrm{sin}(H)=\frac{q}{\sqrt{41}}$

[storm coyote]

oh thanks i got it

[unborn rampart]

;(

[nimble pilot]

so no help needed??

[storm coyote]

@unborn rampart @nimble pilot @storm coyote ,,,, special thanks to @storm coyote

[keen spindle]

@near rivet has given 1 rep to @nimble pilot @vague schooner