#trigonometry
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For 3g, divide the triangle into two right triangles. Such that a=10 and b=a/2
Height(base/2) for the area of one of the two triangles
Then multiply it by 2
For 3h, use sin to find the hypotenuse and then find the remaining side with Pythagorean theorem
nah nah
its slow
do 1/2 ab sin c
you have to use trig
3g doesn’t need trigonometry
Okay i know it says it
H=(7.6-1.2)/sin(31)
The side in question for 3h will be
\sqrt{(\frac{7.6-1.2}{\sin(31)})^2-(7.6-1.2)^2}
M
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he does
bruh
so its
1/2 * 10mm * 10mm * sin(60)
i know sin60 is
root3/2
so its
50mm * root3/2
so its 50root3/2
which cancels
to 25root3
@gloomy kiln understand?
rip
25root3
not root2
kk
its a simple formula to remember ngl
Can be found purely with Pythagorean theorem and 1/2hb
\begin{align}
5^2+b^2=10^2\\
b=\sqrt(75)\\
2\cdot\frac{1}{2}\cdot5\cdot\sqrt(75)\\
5\cdot5\cdot\sqrt(3)\\
25\sqrt(3)
\end{align}
M
BUT IT ASKED TO USE TRIGONOMETRY
OH MY FUCKING DAYS BRO
READ THE QUESTION
IT SAYS USE TRIGONOMETRY
SO ITS 1/2 ab sinC
I said I acknowledge it says to use trigonometry but I was showing you that it’s not necessary. It sounded before like you were saying it was the only way
you need to chill
also don't give the answer directly
moreover M's second answer is implicitly trigonometry as it leverages the properties of a right triangle
i know but the question asks to use trig 😭😭😭
im gonna start tweaking istg
just because M doesn't say "sin" in their answer doesn't mean they aren't using trigonometry, as I've justified, you need a right triangle in any case so both approaches are fine
you don't need to be rude about it
No i understand rion
but the problem is that theyre using pythagoras when the question CLEARLY states to use trig
If you get it, then let's stop it here
yeah fair
nvm you didn't get it
whatever, I cba to explain why M's answer is valid for the third time
no i get it now
but WHY tho
I'm not going to explain a third time, so just take it or leave it