#Hey! Can somebody help me in an exercise considering limits?

1 messages · Page 1 of 1 (latest)

jovial vineBOT
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glad tulip
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send a clear pic with translation?

shy rover
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Ok

glad tulip
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thx

shy rover
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Detérminer is determine and calculer is calculate

shy rover
bitter currentBOT
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@shy rover has given 1 rep to @glad tulip

shy rover
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Is it clear?

glad tulip
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could you send the limit part again

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(srry, i got bad eyes)

shy rover
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it's f(x)

shy rover
glad tulip
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the part below

shy rover
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Ah ok

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It's sending

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x -> + infinity

glad tulip
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Wait, I gotta go somewhere

shy rover
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This was my attempt at it. It was unsuccessful.

glad tulip
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I'll come in 15

shy rover
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Ok take your time. I'll be doing some other exercises

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Thanks once again

lapis dock
shy rover
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Yes sure

lapis dock
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okay the question you posted?

shy rover
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déterminer means determine and calculer means calculate

lapis dock
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okie

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one sec

shy rover
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Ok

shy rover
lapis dock
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am i mistaken?

shy rover
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x - 2sqrt(x)

lapis dock
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oh

shy rover
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and + infinity

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x -> + infinity

lapis dock
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aight

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one sec

shy rover
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ok!

summer duneBOT
shy rover
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yes!

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but positive infinity

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I tried the conjugate method

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It didn't work

lapis dock
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now we can say $\lim_{n\to\infty} \sqrt{x}(\sqrt{x}-2)$

summer duneBOT
lapis dock
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do you see

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why

shy rover
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hmmm

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yes

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because sqrt x times sqrt x equals x

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continue

lapis dock
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yes

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now lets apply the product rule

shy rover
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I'm going to be taking notes

lapis dock
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and also im bending limit laws a little

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but you'll see why this works

shy rover
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Ok

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wait

lapis dock
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now $(\lim_{n\to\infty} \sqrt{x}) (\lim_{n\to\infty} \sqrt{x}-2)$

shy rover
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now you are going to conjugate?

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wtf

lapis dock
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no

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wait smth is wrong

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!

shy rover
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Okay so you are seperating it

lapis dock
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yes

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sry notation is off for sum reason

summer duneBOT
shy rover
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It's alr lol

lapis dock
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okay so

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what are those two limits

shy rover
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the first one is positive infinity

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and the second is also positive infinity

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oh shit

lapis dock
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yep

shy rover
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and positive infinity times positive infinity is positive infinity

lapis dock
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a second explanation is simpler

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the linear function grows faster than the sqrt function

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so technically

shy rover
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can you use simpler terms

lapis dock
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the infinity of a linear function is greater than that of an sqrt

shy rover
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I study math in french

lapis dock
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essentially

shy rover
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Ah ok

lapis dock
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$x>\sqrt{x}$

shy rover
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WHat do you mean by grow?

summer duneBOT
lapis dock
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for x>1

shy rover
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Oh yes because infinity always grows?

lapis dock
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yes

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it tends to

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or the end behavior

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that is what $\lim_{x\to\infty}$ represents

summer duneBOT
shy rover
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because both equal infinity

lapis dock
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no

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infinity is purely a concept

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it is not an actual number

shy rover
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Yes it is not a number

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so we shouldn't compare it? thinksweat

lapis dock
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no...

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we need to compare the graphs

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and how they behave as they

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tend to infinity

shy rover
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ah so the one without sqrt is significantly bigger?

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even though both are growing to infinity

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one is bigger than the other?

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or larger

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or higher? I don't know the term

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in french it's "supérieure"

lapis dock
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i guess so

shy rover
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Thank you

lapis dock
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there is the word

shy rover
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You made me think differently about infinity

lapis dock
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yes

shy rover
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even though I know infinity is not a number. I always thought of it as a big number

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thank you @lapis dock

bitter currentBOT
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@shy rover has given 1 rep to @lapis dock

lapis dock
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yw

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and you can close now

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if you want

shy rover
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yes before I close I have a question. How do you go about managing old lessons from previous years?

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Like how do you remember them?

lapis dock
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uh its just my memory?

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usually i practice concepts so much its just ingrained in my brain

shy rover
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Ah ok

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I haven't touched math for 5 months

lapis dock
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oh

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there are some french people in here that are experts in math

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like noiR or rotor

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you can ask them

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if you have any questions

shy rover
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Ye thanks

lapis dock
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yw

shy rover
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I'll be closing for now

lapis dock
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alright

shy rover
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How can I close

glad tulip
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+close

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type +close

shy rover
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+close