Could someone please confirm if what I have so far is correct and how to proceed?
For a) (idk if this is right but) I got x = (4-2t, 1-3t, -4+4t, t) with t being the free variable
For b) (idk if this is right but) I got x = (8-2t, -9-3t, 7+4t, t) with t being the free variable
For c) (a) Make a system of equations:
4 - 2t ≥ 0
1 - 3t ≥ 0
-4 + 4t ≥ 0
t ≥ 0
I'm getting that this system has no solutions...?
Similarly for (b)
8 - 2t ≥ 0
-9 - 3t ≥ 0
7 + 4t ≥ 0
t ≥ 0
I'm getting that this system also has no solutions?
Feels like I went wrong somewhere, would appreciate if anyone could confirm and tell me where I went wrong...