maths

[gleaming glen]

i need help with 1.67 b.
thanks.

[tribal current]

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   +close
   

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[mortal sail]

x^2+x=0

X=0,-1

Note that 1 can be expressed as 3^0 @gleaming glen

[gleaming glen]

yess i know

thank youu

[mortal sail]

Say that without the second u

[gleaming glen]

so we used log base 3 here?

[gleaming glen]

what do you mean ahha

[mortal sail]

This without the second u

[gleaming glen]

why

[mortal sail]

I suppose

[gleaming glen]

okok

thank you

[mortal sail]

Do u know how to use natural log

[mortal sail]

Tag me

[gleaming glen]

yes i know

[mortal sail]

Do u know ln(a^b)=b *lna

[gleaming glen]

isn’t it e^(ln p) = p

or ln e^k = k

[mortal sail]

There's another use should I explain in dms

[gleaming glen]

why not here

[mortal sail]

I mean I don't mind

Okay look

[gleaming glen]

ok

[mortal sail]

Let ln (a^b)

So there is a property that this is equal to b* lna

Basically the exponent comes outside of log

[mortal sail]

Now for your question

[gleaming glen]

wait what does this mean

[mortal sail]

Using ln on both sides

[mortal sail]

Wait I'll draw it

[gleaming glen]

okok

[mortal sail]

so for youe question

taking ln both sides

[mortal sail]

if u learn this then u wont need to think which base to take

i guess, im not sure lol

[gleaming glen]

ahaha wait let me see

you are not sure 😭

[mortal sail]

i mean u might be having other kinds of questions which might need other bases

but as for the ones u sent just now

u wont

[gleaming glen]

did you write ln a^b = b* lna

[mortal sail]

natural log would solve everything

[mortal sail]

yup

[gleaming glen]

okok

[mortal sail]

it's actually k* lne but since lne = 1 it comes to be k

[gleaming glen]

oh this is a rule

the one i wrote

[mortal sail]

yea these are all interconnected

[gleaming glen]

oh ok

thank you

[mortal sail]

say thank you @mortal sail

[gleaming glen]

+close