#Can anyone verify my answers? I'm not sure.
33 messages · Page 1 of 1 (latest)
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I only disagree with -6 and 6.
hmm why?
I think at point -6, there is no left continuous right?
So, the left continuous will be DNE
there is a small dot at -6, and one at 6
it is unknown how the graph behaves after those points
However, the right continuous is at -6
That only matters if the function is defined on the other side.
After all, we don't say that, for example, f(x) = arcsin(x) is discontinuous at x = ±1.
i would assume it doesn’t exist
I would assume that this is just the whole domain of the function.
In which case there's no problem at x = ±6.
*unless you are wolfram alpha documentation; goodness knows why
You're welcome!
Though, if there's a possibility of seeing whether that would be the correct answer, please share. Maybe they follow Micabo's convention.
Hm, weird...
rude
Both wrong
Agree with that