#how do you find area when you have median and two sides?

66 messages · Page 1 of 1 (latest)

tulip holly
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idk what to do

nocturne relicBOT
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fair verge
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@tulip holly Can you send a picture of your question?

silent perch
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do you mean angle?

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if so then you use 0.5 * side a * side b * sin(C)

fair verge
frail onyx
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its like the line which joins the middle of the opposite side

silent perch
silent perch
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area = base*height/2

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is for right angle

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and scalene

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and isoceles

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however if youre doing trigonometry

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its 1/2 * a* b * sinC

frail onyx
silent perch
frail onyx
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of the point

pallid plover
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Try duplicating the traingle and rotate it so that the median in in line and BC matches

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it proves 1/2 absin(c)

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although you need angle to find median

silent perch
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wait no its a line from the top to the base

silent perch
frail onyx
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yes

fair verge
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if you have median length and two sides length

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I believe this relation could be useful

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I was summoned

fair verge
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Yes I can do that

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Right lemmie get my math book

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Ok, so. The formula to find the area of a triangle is Base times Hight times Two

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Ah devided by two..

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Right devided

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B * H / 2 = A

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The height here is the Median

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So you need to find D, the base, and times it by Median, the height

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$$ c^2 * n + b^2 m = a(d^2+mn) $$

fervent sleetBOT
fair verge
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Here since its the median, m = n

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Thus we get

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How does m = n?

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ah wait I see

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Because its the median

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median is NOT the height

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d is the median, no?

fair verge
fair verge
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Since n = m and a = m/2 = n /2
$$ a/2( c^2 + b^2 ) = a(d^2 + (a/2)^2 ) $$

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Right

fervent sleetBOT
fair verge
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So with this relation you can find the third side, then probably apply Heron's Formula to get the area

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@tulip holly

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Oh wait I haven't even touched on this subject yet

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Why r u in the ticket

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?

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Ahh I see you're smarter!

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I deem myself useless, Triangles are easy and you've got this Coffey!

fair verge
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You can search up Stewart's theorem for more or Appolonius theorem