#What's a singular point? And is it different from a critical point?

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plain flicker
sacred spearBOT
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amber jasper
timber atlas
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Perhaps a critical point at which the derivative doesn't exist?

amber jasper
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so u need to find $k$ such that $0 + 2\arcsin(e^0) = k - ln(0+1)$

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right?

plain flicker
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nah i just want the b exercise

buoyant quarryBOT
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neruguis

amber jasper
plain flicker
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the a is just there to look good

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it dont matte

timber atlas
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I think you should just determine whether the critical point x = 0 is an extremum point or not.

plain flicker
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i also do

amber jasper
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lemme graph it to understand

plain flicker
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im absolutely almost certain

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but why the hell did they call it a singular point

timber atlas
plain flicker
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oh yeah it isnt

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thats a part of the exercise

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since, in b they give you that k

amber jasper
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well if k = 4

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then it’s not continuous

timber atlas
amber jasper
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I know

plain flicker
amber jasper
plain flicker
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heres a solution of a similar exercise

amber jasper
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ok

plain flicker
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apparently is when it isnt differentiable

amber jasper
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okokok

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so their derivatives are different

plain flicker
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yuh uh

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this isnt in the class papers though

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thanks college

amber jasper
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ok

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so even if k = π, it’s not differentiable

plain flicker
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bit of an issue

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well , if you give k the right value to be the same result

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as the other equation

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it probably is

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but oh well

amber jasper
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I didn’t got what’s a singular point

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but I think the question is a bit confusing

plain flicker
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its a point where differentials give different values

amber jasper
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even understanding the language too

plain flicker
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in 0-

amber jasper
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and 0+

plain flicker
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and à

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0+

amber jasper
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à?

timber atlas
amber jasper
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yeah

timber atlas
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In any case, just prove that x = 0 is a maximum point. Should be pretty easy.

plain flicker
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yup

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the rest is easily done

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thanks

amber jasper
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+close it

plain flicker
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+close