#why did we switch from 3cosθ -> 3sinθ and 2sinθ -> 2cosθ?

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storm glacierBOT
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novel rivet
harsh fog
# novel rivet

I don't recognize the notation, but this kind of area maximization problem is typically solved with calculus, i.e. derivatives.

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So you would want to find the area of the quadrilateral as a function of theta, then take the derivative of that function.

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And d/dx sin(x) = cos(x) and d/dx cos(x) = -sin(x).

novel rivet
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ahhh I think I get it now thanks

clever crag
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+close