#how to do this
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the plane is tangent to the surface, when does that happen?
the gradient is collinear with the normal of the plane, which is (1,2,3)
this implies x=z=-y at a touching point, now we can guess a touching point with the surface equation: x^2-2y^2+3z^2=2 for example we can take (x,y,z)=(1,-1,1), thus p = 1-2+3=2
@gaunt plinth
that is definitely not gradient
In this section discuss how the gradient vector can be used to find tangent planes to a much more general function than in the previous section. We will also define the normal line and discuss how the gradient vector can be used to find the equation of the normal line.
to take your example even
the paraboloid z = x^2 + y^2
its tangent surface at (0,0) is simply the xy plane
the gradient at (0,0) is (0,0,-1)
@gaunt plinth
revise definitions
i think you are incorrectly applying your intuition about single variable derivatives to 3d space
e.g for y=x^2 the derivative at 0 is 0, but that's not gradient
the gradient is (0,-1)
which is again normal to the tangent line
x=z=-y?
How it came
Rest i understood
Ohh you compared both coefficients of plane and curve
1 1
2 -2
3 3
So it gives (1 -1 1)
the normal of the plane is (1,2,3) where as the gradient of the surface is (2x,-2y,6z)
these vectors must be collinear
@gaunt plinth

What happened?
You did mistake in derivative
2x-4y+6z
@fallen basalt
this is a multivariable function
there is no "derivative"
you can speak of partial derivatives or total derivative
@gaunt plinth
Yeah