#how to do this

48 messages · Page 1 of 1 (latest)

gaunt plinth
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Any hints

cobalt otterBOT
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fallen basalt
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the plane is tangent to the surface, when does that happen?

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the gradient is collinear with the normal of the plane, which is (1,2,3)

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this implies x=z=-y at a touching point, now we can guess a touching point with the surface equation: x^2-2y^2+3z^2=2 for example we can take (x,y,z)=(1,-1,1), thus p = 1-2+3=2

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@gaunt plinth

gaunt plinth
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How are they colinear?

fallen basalt
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that is definitely not gradient

fallen basalt
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to take your example even

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the paraboloid z = x^2 + y^2

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its tangent surface at (0,0) is simply the xy plane

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the gradient at (0,0) is (0,0,-1)

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@gaunt plinth

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revise definitions

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i think you are incorrectly applying your intuition about single variable derivatives to 3d space

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e.g for y=x^2 the derivative at 0 is 0, but that's not gradient

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the gradient is (0,-1)

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which is again normal to the tangent line

gaunt plinth
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How it came

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Rest i understood

gaunt plinth
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Ohh you compared both coefficients of plane and curve

1 1
2 -2
3 3

So it gives (1 -1 1)

fallen basalt
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these vectors must be collinear

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@gaunt plinth

gaunt plinth
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Got it perfectly

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Thank you dear

fallen basalt
gaunt plinth
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You did mistake in derivative

2x-4y+6z

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@fallen basalt

fallen basalt
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this is a multivariable function

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there is no "derivative"

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you can speak of partial derivatives or total derivative

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@gaunt plinth

gaunt plinth
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Yeah

fallen basalt
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i dont understand what this means

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where is the gradient?

gaunt plinth
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(2x,-4y,6z)

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And it is colinear with (123) so i divided by 3

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And i got (1 -2 3)

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Now compared

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And i see (1 -1 1)